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To make Reagent A, we will need to make a solution of 10.0 g of sulfanilamide in 1 L of 2.4 molar hydrochloric acid (HCI). The stock solution of HCI is 12 molar HCI. How many milliliters (mL) of 12 M HCI would you add to produce 0.5 liters (L) of 2.4M HCI? mL HCI After creating 0.5 L of 2.4 molar HCI solution, how many grams of sulfanilamide will be added? g sulfanilamide

To make Reagent A, we will need to make a solution of 10.0 g of sulfanilamide in 1 L of 2.4 molar hydrochloric acid (HCI). The stock solution of HCI is 12 molar HCI. How many milliliters (mL) of 12 M HCI would you add to produce 0.5 liters (L) of 2.4M HCI? mL HCI After creating 0.5 L of 2.4 molar HCI solution, how many grams of sulfanilamide will be added? g sulfanilamide

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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In order to analyze water samples using a spectrophotometer or plate reader, it is necessary to turn the molecules of nitrate into a dye molecule that can be quantified. The first step in turning nitrate (NO3) into a dye molecule is reducing it to a molecule of nitrite (NO2). This is done by reacting the NO3 with cadmium. After the reduction reaction, the NO2 is reacted with two additional reagents. The first reagent, Reagent A, is a solution of sulfanilamide and hydrochloric acid. The second reagent, Reagent B, is a solution of N-(1-naphthyl)-ethylenediamine, called NNED for short. The compounds are mixed with the water sample and produce a purple color. The intensity of the purple color is directly related to the concentration of nitrite in the water sample. We can measure how purple the water turns as absorbance on a spectrophotometer and then convert the absorbance to concentration of nitrate. To make Reagent A, we will need to make a solution of 10.0 g of sulfanilamide in 1 L of 2.4 molar hydrochloric acid (HC). The stock solution of HCı is 12 molar HCI. How many milliliters (mL) of 12 M HCI would you add to produce 0.5 liters (L) of 2.4M HCI? mL HCI After creating 0.5 L of 2.4 molar HCI solution, how many grams of sulfanilamide will be added? g sulfanilamide
Transcribed Image Text:In order to analyze water samples using a spectrophotometer or plate reader, it is necessary to turn the molecules of nitrate into a dye molecule that can be quantified. The first step in turning nitrate (NO3) into a dye molecule is reducing it to a molecule of nitrite (NO2). This is done by reacting the NO3 with cadmium. After the reduction reaction, the NO2 is reacted with two additional reagents. The first reagent, Reagent A, is a solution of sulfanilamide and hydrochloric acid. The second reagent, Reagent B, is a solution of N-(1-naphthyl)-ethylenediamine, called NNED for short. The compounds are mixed with the water sample and produce a purple color. The intensity of the purple color is directly related to the concentration of nitrite in the water sample. We can measure how purple the water turns as absorbance on a spectrophotometer and then convert the absorbance to concentration of nitrate. To make Reagent A, we will need to make a solution of 10.0 g of sulfanilamide in 1 L of 2.4 molar hydrochloric acid (HC). The stock solution of HCı is 12 molar HCI. How many milliliters (mL) of 12 M HCI would you add to produce 0.5 liters (L) of 2.4M HCI? mL HCI After creating 0.5 L of 2.4 molar HCI solution, how many grams of sulfanilamide will be added? g sulfanilamide
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