A buffer was made with HC2H3O2 and its conjugate base. What is the pH of the buffer if at equilibrium there was [HC2H3O2] = 0.5000 M and [C2H3021] = 0.7000 M and the Ka = 1.60 x 10-5 ? everything is based upon the acid dissolving in water: HC2H3O2 + H20 <-> C2H3O21 + H3o+1 [ Ka = solve for [H30*1] then put in the numbers Ka [ [H3O*1] =- [ [H30*1] = pH = - log
A buffer was made with HC2H3O2 and its conjugate base. What is the pH of the buffer if at equilibrium there was [HC2H3O2] = 0.5000 M and [C2H3021] = 0.7000 M and the Ka = 1.60 x 10-5 ? everything is based upon the acid dissolving in water: HC2H3O2 + H20 <-> C2H3O21 + H3o+1 [ Ka = solve for [H30*1] then put in the numbers Ka [ [H3O*1] =- [ [H30*1] = pH = - log
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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![A buffer was made with HC2H3O2 and its conjugate base. What is the pH of the buffer if at equilibrium there was
[HC2H3O2] = 0.5000 M and [C2H302ª] = 0.7000 M and the Ka = 1.60 x 10-5 ?
everything is based upon the acid dissolving in water:
HC2H3O2
+ H20 <-> C2H3O21 + H30*1
[
Ka =
[
solve for [H30*'] then put in the numbers
Ka [
(
[H3O+1] :
[
]
[H3O+'] =
pH = - log
d. HC6H6O61
f. SO3?
a. H30+1
b. Он1
c. H2C6H606
е. HSO31
-2
g. H2SO3
h. HC2H3O2
i. C2H3O21
j. H2S
k. HS-1
I. s2
m. HX
п. X-1
О. 1
р. 2
q. 3
r. 0.5000
s. 5.5 X 10-5
t. 3.5 X 10-4
u. 8.00 x 10-5
v. 1.75 x 10-6
w. 1.11 x 10-8
х. 5.5 х 102
y. 0.7000
z. 1.60 x 10-5
аа. 1.143 х 10-5
bb. 0.4900
сс. 1.104 х 10-5
dd. 0.7100
ее. 1.26 х 10-5 ff. 4.901
gg. 7.93
hh. 4.942
ii. 4.957](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F03121ea6-6cc9-419a-9866-a8a4918051de%2F48db7660-27b6-4da1-a9bc-707ba7b0459b%2F6ua99p_processed.png&w=3840&q=75)
Transcribed Image Text:A buffer was made with HC2H3O2 and its conjugate base. What is the pH of the buffer if at equilibrium there was
[HC2H3O2] = 0.5000 M and [C2H302ª] = 0.7000 M and the Ka = 1.60 x 10-5 ?
everything is based upon the acid dissolving in water:
HC2H3O2
+ H20 <-> C2H3O21 + H30*1
[
Ka =
[
solve for [H30*'] then put in the numbers
Ka [
(
[H3O+1] :
[
]
[H3O+'] =
pH = - log
d. HC6H6O61
f. SO3?
a. H30+1
b. Он1
c. H2C6H606
е. HSO31
-2
g. H2SO3
h. HC2H3O2
i. C2H3O21
j. H2S
k. HS-1
I. s2
m. HX
п. X-1
О. 1
р. 2
q. 3
r. 0.5000
s. 5.5 X 10-5
t. 3.5 X 10-4
u. 8.00 x 10-5
v. 1.75 x 10-6
w. 1.11 x 10-8
х. 5.5 х 102
y. 0.7000
z. 1.60 x 10-5
аа. 1.143 х 10-5
bb. 0.4900
сс. 1.104 х 10-5
dd. 0.7100
ее. 1.26 х 10-5 ff. 4.901
gg. 7.93
hh. 4.942
ii. 4.957
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