A buffer solution is prepared which is 0.140 M both in lactic acid (CH3CHOHCO₂H) and in sodium lactate (CH3CHOHCO₂Na).1.38×10-4 for lactic acid.KaWhat is the pH of this solution?=3.860You are correct.Your receipt no. is 153-562When 1.94 mL of 0.120 M HCI is added to 11.0 mL of this buffer solution, what is resulting change in pH?0.11Previous TriesSubmit Answer Incorrect. Tries 33/99 Previous TriesThis discussion is closed.

Answer:- This question is answered by using the simple concept of calculation of pH of a buffer…

A buffer solution is prepared which is 0.140 M both in lactic acid (CH3CHOHCO₂H) and in sodium lactate (CH3CHOHCO₂Na). Ka = 1.38×10-4 for lactic acid. What is the pH of this solution? 3.860 You are correct. Your receipt no. is 153-562 ? Previous Tries When 1.94 mL of 0.120 M HCl is added to 11.0 mL of this buffer solution, what is resulting change in pH? 0.11 Submit Answer Incorrect. Tries 33/99 Previous Tries This discussion is closed.

A buffer solution is prepared which is 0.140 M both in lactic acid (CH3CHOHCO₂H) and in sodium lactate (CH3CHOHCO₂Na). Ka = 1.38×10-4 for lactic acid. What is the pH of this solution? 3.860 You are correct. Your receipt no. is 153-562 ? Previous Tries When 1.94 mL of 0.120 M HCl is added to 11.0 mL of this buffer solution, what is resulting change in pH? 0.11 Submit Answer Incorrect. Tries 33/99 Previous Tries This discussion is closed.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.

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A buffer solution is prepared which is 0.140 M both in lactic acid (CH3CHOHCO₂H) and in sodium lactate (CH3CHOHCO₂Na).
1.38×10-4 for lactic acid.
Ka
What is the pH of this solution?
=
3.860
You are correct.
Your receipt no. is 153-562
When 1.94 mL of 0.120 M HCI is added to 11.0 mL of this buffer solution, what is resulting change in pH?
0.11
Previous Tries
Submit Answer Incorrect. Tries 33/99 Previous Tries
This discussion is closed.

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