to investigate the different colors of M&Ms in a bag! since I am not made of money, I can only afford for us to do a test based off of a fun-si Now, you cannot EAT your candy!!! (right now...) t the number of candies in your bag: _102 the chart with your information: plor Red Yellow Blue Brown Orange Green punt 14 11 10 37 11 19 ortion 0.14 0.11 0.10 0.36 0.11 0.19 ing at your data, you are going to test each claimed color given below. (Don't worry, we reaking rules – we will use the class data in a moment to actually conduct the test ©) F ne blank with <, >, or # based on what you found in your bag. n: H.: p = 0.13 vs H.: p> 0.13 Red: H.: p = 0.13 vs H.: p < 0.13 H,: p = 0.20 vs H,: p_< 0.20 Orange: H,: p = 0.15 vs H,: p > 0.15 n: H,: p = 0.15 vs H,: p < 0.15 Blue: H,: p = 0.24 vs H,: p < 0.24 bile the data from the rest of the class: lor Brown Red Yellow Orange Green Blue unt 15 14 30 19 11 12

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Author:Amos Gilat
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Unit 6 – Inference for Categorical Data: Proportions
M&M Activity
Name:
Have you ever opened a bag of M&Ms and been surprised at the distribution of colors? We are
going to investigate the different colors of M&Ms in a bag!
Now, since I am not made of money, I can only afford for us to do a test based off of a fun-size
pack. Now, you cannot EAT your candy!!! (right now...)
Count the number of candies in your bag: _102
Fill in the chart with your information:
Color
Brown
Red
Yellow
Orange
Green
Blue
Count
14
11
10
37
11
19
Proportion
0.14
0.11
0.10
0.36
0.11
0.19
Looking at your data, you are going to test each claimed color given below. (Don't worry, we are
not breaking rules – we will use the class data in a moment to actually conduct the test e) Fill
in the blank with <, >, or + based on what you found in your bag.
Brown: Ho: p = 0.13 vs H.: p > 0.13
Red: Ho: p = 0.13 vs H,: p < 0.13
Yellow: Ho: p = 0.20 vs H,: p _< 0.20
Orange: H,: p = 0.15 vs H,: p > 0.15
Green: H,: p = 0.15 vs H,: p < 0.15
Blue: H,: p = 0.24 vs H,: p < 0.24
Compile the data from the rest of the class:
Color
Brown
Red
Yellow
Orange
Green
Blue
Count
15
14
30
19
11
12
Proportion
0.12
0.15
0.14
0.30
0.19
0.11
Perform each significance test on the next page using a = 0.10.
Transcribed Image Text:Unit 6 – Inference for Categorical Data: Proportions M&M Activity Name: Have you ever opened a bag of M&Ms and been surprised at the distribution of colors? We are going to investigate the different colors of M&Ms in a bag! Now, since I am not made of money, I can only afford for us to do a test based off of a fun-size pack. Now, you cannot EAT your candy!!! (right now...) Count the number of candies in your bag: _102 Fill in the chart with your information: Color Brown Red Yellow Orange Green Blue Count 14 11 10 37 11 19 Proportion 0.14 0.11 0.10 0.36 0.11 0.19 Looking at your data, you are going to test each claimed color given below. (Don't worry, we are not breaking rules – we will use the class data in a moment to actually conduct the test e) Fill in the blank with <, >, or + based on what you found in your bag. Brown: Ho: p = 0.13 vs H.: p > 0.13 Red: Ho: p = 0.13 vs H,: p < 0.13 Yellow: Ho: p = 0.20 vs H,: p _< 0.20 Orange: H,: p = 0.15 vs H,: p > 0.15 Green: H,: p = 0.15 vs H,: p < 0.15 Blue: H,: p = 0.24 vs H,: p < 0.24 Compile the data from the rest of the class: Color Brown Red Yellow Orange Green Blue Count 15 14 30 19 11 12 Proportion 0.12 0.15 0.14 0.30 0.19 0.11 Perform each significance test on the next page using a = 0.10.
d
Orange:
Green:
Blue:
St H.: p = 0.15 vs H.: p
0.15 H.: p = 0.15 vs H.: p.
0.15 H.: p = 0.24 vs H,: p .
0.24
p=
p=
e
Random
Random
Random
Independent -
PI
Independent –
Independent –
Large Counts -
Large Counts
Large Counts
Test Statistic =
Test Statistic =
Test Statistic =
Do
P-value =
P-value =
P-value =
Co
e
Transcribed Image Text:d Orange: Green: Blue: St H.: p = 0.15 vs H.: p 0.15 H.: p = 0.15 vs H.: p. 0.15 H.: p = 0.24 vs H,: p . 0.24 p= p= e Random Random Random Independent - PI Independent – Independent – Large Counts - Large Counts Large Counts Test Statistic = Test Statistic = Test Statistic = Do P-value = P-value = P-value = Co e
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