4 kids have just received a large bag of candy pieces at a friend's birthday party each. The mean number of pieces of candy received in the bag per kid is 136. The numbers of pieces of candy for 3 of the kids are listed below. The number of pieces the fourth kid got is unknown. 164, 128, 132 Did the fourth kid receive more than, fewer than, or equal to 136 pieces? A More than 136 pieces B Fewer than 136 pieces Equal to 136 pieces

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
icon
Related questions
icon
Concept explainers
Question
**Understanding Mean and Distribution of Values: An Educational Insight**

**Scenario:**
Four kids have just received a large bag of candy pieces at a friend's birthday party each. The mean number of pieces of candy received in the bag per kid is 136. The numbers of pieces of candy for 3 of the kids are listed below. The number of pieces the fourth kid got is unknown.

- 164, 128, 132

**Question:**
Did the fourth kid receive:
A) More than 136 pieces
B) Fewer than 136 pieces
C) Equal to 136 pieces

**Detailed Explanation:**

To find out whether the fourth kid received more, fewer, or equal to 136 pieces, we start by calculating the total number of pieces of candy, given that the mean per kid is 136.

1. **Calculating Total Pieces of Candy:**
   The mean number of pieces is 136, and there are 4 kids.

   \[
   \text{Total pieces of candy} = \text{Mean} \times \text{Number of kids} = 136 \times 4 = 544 \text{ pieces}
   \]

2. **Determining Pieces for the Fourth Kid:**
   The numbers of pieces for 3 kids are: 164, 128, 132.

   \[
   \text{Sum of pieces for 3 kids} = 164 + 128 + 132 = 424 \text{ pieces}
   \]

   Given the total pieces of candy for all 4 kids, we can find out the pieces received by the fourth kid:

   \[
   \text{Number of pieces for the fourth kid} = \text{Total pieces} - \text{Sum of pieces for 3 kids} = 544 - 424 = 120 \text{ pieces}
   \]

3. **Comparison with Mean:**
   The fourth kid received 120 pieces of candy. Since 120 is less than the mean (136):

   \[
   \boxed{B) \text{Fewer than 136 pieces}}
   \]

From the calculations, the answer to the question is that the fourth kid received fewer than 136 pieces.
Transcribed Image Text:**Understanding Mean and Distribution of Values: An Educational Insight** **Scenario:** Four kids have just received a large bag of candy pieces at a friend's birthday party each. The mean number of pieces of candy received in the bag per kid is 136. The numbers of pieces of candy for 3 of the kids are listed below. The number of pieces the fourth kid got is unknown. - 164, 128, 132 **Question:** Did the fourth kid receive: A) More than 136 pieces B) Fewer than 136 pieces C) Equal to 136 pieces **Detailed Explanation:** To find out whether the fourth kid received more, fewer, or equal to 136 pieces, we start by calculating the total number of pieces of candy, given that the mean per kid is 136. 1. **Calculating Total Pieces of Candy:** The mean number of pieces is 136, and there are 4 kids. \[ \text{Total pieces of candy} = \text{Mean} \times \text{Number of kids} = 136 \times 4 = 544 \text{ pieces} \] 2. **Determining Pieces for the Fourth Kid:** The numbers of pieces for 3 kids are: 164, 128, 132. \[ \text{Sum of pieces for 3 kids} = 164 + 128 + 132 = 424 \text{ pieces} \] Given the total pieces of candy for all 4 kids, we can find out the pieces received by the fourth kid: \[ \text{Number of pieces for the fourth kid} = \text{Total pieces} - \text{Sum of pieces for 3 kids} = 544 - 424 = 120 \text{ pieces} \] 3. **Comparison with Mean:** The fourth kid received 120 pieces of candy. Since 120 is less than the mean (136): \[ \boxed{B) \text{Fewer than 136 pieces}} \] From the calculations, the answer to the question is that the fourth kid received fewer than 136 pieces.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Knowledge Booster
Conditional Probability, Decision Trees, and Bayes' Theorem
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, geometry and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
Geometry
ISBN:
9781337614085
Author:
Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:
Cengage,
Elementary Geometry for College Students
Elementary Geometry for College Students
Geometry
ISBN:
9781285195698
Author:
Daniel C. Alexander, Geralyn M. Koeberlein
Publisher:
Cengage Learning