To convert 20 g of ice at -5oC to 120oC to steam you need _______ cal of energy?

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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I need help with a homework question I did the answer but it’s incorrect and I have to redo it to get the correct one and why it’s correct and also explain my wrong answer and why it’s wrong. To convert 20 g of ice at -5oC to 120oC to steam you need _______ cal of energy? Assume specific heat as 1 for all three phases. My answer: Mass of ice (m)= 20 g 20x10-^3 KG specific heat of water (c)= ikal/kg C2 T1= -10 degrees T2= 110 degrees C =T^2-T^1 =110 degrees -(-10 degrees) =120 degrees So the. The energy is supplied to the water because the energy gains by water which is equal to mass of water x specific heat x change in temperature water = MX2XT 20x10^a3kg x 1kcal/kg degrees c x 120 degrees C I have to explain why it’s wrong and then I have to figure out how to make this correct because I’m trying to do well on this homework assignment even though this was tricky to try to find a good correct answer for this and to explain why it’s correct
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