The data below are for water (H₂O)BoilingPointHeat ofSH Capacity(solid)SH Capacity(liquid)SH Capacity(vapor)Vaporization334 J/g2260 J/g2.05 J/gºC4.18 J/g °C1.90 J/gºC1. Draw a heating curve for substance water, going from -20°C to 125°C on the axis below.Write in all formulas used to calculate heat.125°CMeltingpoint0.0°C100°C-OC100.0°CTemp->FEHeat ofFusionq=MAHFUEmSs4Tq=m4Hvapq=mSLATq=mSVATBOMSAT19=heatm=massAT=(T₂-T)-Change-20°C-Timeb. Determine the amount of heat necessary to convert 15.0g of water at 100.0°C to steam at 100.0°C.G=m4HvaporizationHvaporization=2260)/g-33900)9AH 2260/9q=S-specific heat9=159x22601/9c. Determine the amount of heat necessary to convert 15.0g of ice at 0.0°C to liquid at 0.0° C.9-15gx3349=159x2260AH =9-mAhfusion-meltingmAltraporization boiling4-50105All-384 3gΔΗAH vaporization=2260/gd. Determine the amount of heat given off when 25g of water cools from 56.2°C to 33.5°C.25x4-18x(-22.7) = -2372.15)-2372.15)=-94.9)/825ge. Determine the amount of heat needed to raise the temperature of 19.6g of X from -15°C to 2.0°C9=2.3kg411--94.93/9ΔΗ =Temp18

(a) To draw the heating curve for water from -20°C to 150°C, given the ∆Hfus (water)= 334 J/g∆Hvap…

Answered: The data below are for water (H₂O)…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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The data below are for water (H₂O)
Boiling
Point
Heat of
SH Capacity
(solid)
SH Capacity
(liquid)
SH Capacity
(vapor)
Vaporization
334 J/g
2260 J/g
2.05 J/gºC
4.18 J/g °C
1.90 J/gºC
1. Draw a heating curve for substance water, going from -20°C to 125°C on the axis below.
Write in all formulas used to calculate heat.
125°C
Melting
point
0.0°C
100°C-
OC
100.0°C
Temp->
F
E
Heat of
Fusion
q=MAHFU
EmSs4T
q=m4Hvap
q=mSLAT
q=mSVAT
B
OMSAT
19=heat
m=mass
AT=(T₂-T)-Change
-20°C-
Time
b. Determine the amount of heat necessary to convert 15.0g of water at 100.0°C to steam at 100.0°C.
G=m4Hvaporization
Hvaporization=2260)/g
-33900)
9
AH 2260/9
q=
S-specific heat
9=159x22601/9
c. Determine the amount of heat necessary to convert 15.0g of ice at 0.0°C to liquid at 0.0° C.
9-15gx334
9=159x2260
AH =
9-mAhfusion-melting
mAltraporization boiling
4-50105
All-384 3g
ΔΗ
AH vaporization=2260/g
d. Determine the amount of heat given off when 25g of water cools from 56.2°C to 33.5°C.
25x4-18x(-22.7) = -2372.15)
-2372.15)=-94.9)/8
25g
e. Determine the amount of heat needed to raise the temperature of 19.6g of X from -15°C to 2.0°C
9=2.3kg
411--94.93/9
ΔΗ =
Temp
18

Expert Solution

Step 1

(a) To draw the heating curve for water from $- 20 ° C$ to $150 ° C$ , given the

$\begin{array}{rcl} ∆ H_{f u s} (w a t e r) & = & 334 J / g \\ ∆ H_{v a p} (w a t e r) & = & 2260 J / g \\ S H c a p a c i t y (S o l i d) & = & 2.05 J / g ° C \\ S H c a p a c i t y (l i q u i d) & = & 4.18 J / g ° C \\ S H c a p a c i t y (V a p o r) & = & 1.90 J / g ° C \end{array}$

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