rounded yold Calloway 5th The data below are for water (1₂0) Boiling Point Melting point Heat of Vaporization SH Capacity (solid) SH Capacity (liquid) 334 J/g 100.0°C 2260 J/g 2.05 J/gºC 4.18 J/gºC 1.90 J/gºC 1. Draw a heating curve for substance water, going from -20°C to 125°C on the axis below. Write in all formulas used to calculate heat. 125°C 100 °C 0.0°C Temp- ос- -20°C- E Heat of Fusion q=MAHFUS EmSs 4T 9-30-22 с 2=159x22600/9 q=m4Hvap q=mseAT SH Capacity (vapor) B q-msVAT 9= AH = MSAT Gheat m=mass AT-(2-1)-Change Time -> b. Determine the amount of heat necessary to convert 15.0g of water at 100.0°C to steam at 100.0°C. G=m4Hvaporization Hvaporization=2260/9 -33900) 9 AH 2260/9 S-specific heat ind Temp 9-mAHfusion-melting mAlvaporization tbolling c. Determine the amount of heat necessary to convert 15.0g of ice at 0.0°C to liquid at 0.0° C.

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old Calloway 5th
The data below are for water (H₂O)
Boiling
Point
125°C
100 °C
Melting
Heat of
Vaporization
point
0.0°C
100.0°C
334 J/g
2260 J/g
1. Draw a heating curve for substance water, going from -20°C to
Write in all formulas used to calculate heat.
OC
Temp
-20°C-
F
Heat of
Fusion
Ng mAHRUS
EmSs4T
9-30-22
SH Capacity SH Capacity
(solid) (liquid)
2.05 J/gºC
с
4.18 J/gºC
125°C on the axis below.
axis below.
q=m4Hvap
q=mseAT
9=
SH Capacity
(vapor)
1.90 J/gºC
ΔΗ =
q=mSVAT
B
OMSAT
-G-heat
m=mass
AT (12-1)-Change
Time -
b. Determine the amount of heat necessary to convert 15.0g of water at 100.0°C to steam at 100.0°C.
q=m4Hvaporization
Hvaporization=2260)/g
-33900)
9
9=159-22003/9
AH 2260/9
c. Determine the amount of heat necessary to convert 15.0g of ice at 0.0°C to liquid at 0.0° C.
Temp
S-specific heat
qmAHfusion-melting
EMAHvaporization toolling
Transcribed Image Text:rounded old Calloway 5th The data below are for water (H₂O) Boiling Point 125°C 100 °C Melting Heat of Vaporization point 0.0°C 100.0°C 334 J/g 2260 J/g 1. Draw a heating curve for substance water, going from -20°C to Write in all formulas used to calculate heat. OC Temp -20°C- F Heat of Fusion Ng mAHRUS EmSs4T 9-30-22 SH Capacity SH Capacity (solid) (liquid) 2.05 J/gºC с 4.18 J/gºC 125°C on the axis below. axis below. q=m4Hvap q=mseAT 9= SH Capacity (vapor) 1.90 J/gºC ΔΗ = q=mSVAT B OMSAT -G-heat m=mass AT (12-1)-Change Time - b. Determine the amount of heat necessary to convert 15.0g of water at 100.0°C to steam at 100.0°C. q=m4Hvaporization Hvaporization=2260)/g -33900) 9 9=159-22003/9 AH 2260/9 c. Determine the amount of heat necessary to convert 15.0g of ice at 0.0°C to liquid at 0.0° C. Temp S-specific heat qmAHfusion-melting EMAHvaporization toolling
Expert Solution
Step 1

Cooling curve is the plot of temperature versus time

The independent variable which is the variable on the X axis is time

The dependent variable which is the variable on the Y axis is Temprature

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