Laboratory 9Titration ofWhite VinegarNAME:INSTRUCTOR:Titrant:Sample:0.210Initial NaOHvolumeFinal NaOH volumeDelivered NaOH volumeCalculations: Show your workAverage titration volumeM NaOHgrams of acetic acid x 10010.0 grams of samplemL VingarTrial 1OmL75-7 mL15.7 mL15.60.0756Moles of NaOHMoles of acetic acidMolarity of acetic acidGrams of acetic acid (molar mass = 60 g/mol)DATE:LABORATORY 9 | TITRATION OF WHITE VINEGARSECTION:15.6 mLmolesTrail 20 mL75.6 mLmolesmL 75.6mxlx 0.0012-0.0756ImxtLmol/LgramsMass% of acetic acid in vinegarREPORT FORM129{

Titration of White Vinegar NAME: INSTRUCTOR: Titrant: Sample: 0.2 10 Initial NaOHvolume Final NaOH volume M NaOH Calculations: Show your work Average titration volume mL Vingar Trial 1 O mL 75.7 mL Delivered NaOH volume 15.7 mL 150 15.6 0.0756 L DATE: SECTION: Trail 2 0 mL 75.6 mL 15.6 mL REPORT FORM mL 75.6mxLx 0.0012-0.07 Imxt

Titration of White Vinegar NAME: INSTRUCTOR: Titrant: Sample: 0.2 10 Initial NaOHvolume Final NaOH volume M NaOH Calculations: Show your work Average titration volume mL Vingar Trial 1 O mL 75.7 mL Delivered NaOH volume 15.7 mL 150 15.6 0.0756 L DATE: SECTION: Trail 2 0 mL 75.6 mL 15.6 mL REPORT FORM mL 75.6mxLx 0.0012-0.07 Imxt

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Drops of HCl
Data: Mass of Sodium Acetate :4.0 g Volume of Sodium Acetate Solution: 100.00mL Acetic Acid Concentration (mass percent from label) :4.5% pH of Prepared Buffer Solutions Buffer Solution Acetic Acid; 4.5% Sodium Acetate Solution Recorded pH A 5.0 mL 5.0 mL 4.3 B 5.0 mL 1.0 mL 4.2 C 10.0 mL 1.0 mL 3.4 D 1.0 mL 10.0 mL 5.0 E 1.0 mL 5.0 mL 4.5 The answers must have the correct units and the correct number of significant figures 1. Sodium acetate moles __________________________ (molar mass = 82.0 g/mol) Molarity of sodium acetate = _______________________ Concentration of acetic acid (from bottle) = ____________ Molarity of acetic acid = ___________________________ (molar mass = 60.0 g/mol; density of the solution is 1.0 g/mL)
MISSED THIS? Watch IWE 14.4; Read Section 14.6. You can click on the Review link to access the section in your e Text. Four solutions of unknown NaOH concentration are titrated with solutions of HC1. The following table lists the volume of each unknown NaOH solution, the volume of HCl solution required to reach the equivalence point, and the concentration of each HCl solution. NaOH volume (mL) 6.00 22.00 14.00 28.00 HCl volume [HC1] (mL) (M) 7.97 0.1799 11.24 10.95 33.18 0.1311 0.0789 0.1421 Part C Calculate the concentration (in M) of the unknown NaOH solution in the third case. NaOH volume (mL) HCl volume (mL) [HC1] (M) 14.00 10.95 0.0789 Express your answer using three significant figures. concentration = Submit Part D 15 ΑΣΦ Request Answer ? Express your answer using four significant figures. P Pearson Review | Constants | Periodic Table M Calculate the concentration (in M) of the unknown NaOH solution in the fourth case. NaOH volume (mL) HCl volume (mL) 28.00 33.18 [HC1] (M)…
INTRODUCTION LABORATORY SIMULATION 1) Calculate the pH of a solution prepared by dissolving 2.35 g of sodium acetate, CH3COONa, in 78.0 mL of 0.10 Macetic acid, CH;COOH(aq). Assume the volume change upon dissolving the sodium acetate is negligible. Ka of CH3COOH is 1.75 x 10-5. pH E METHODS O RESET P MY NOTES A LAB DATA SHOW LABELS