Time left 1:3 The figure below shows a fluid inside a cubical container of side 1 m. If the pressures inside and outside the container is as shown in the figure, what is the net force on one wall of the container

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### Pressure and Force in a Cubical Container

#### Problem Statement:
The figure below shows a fluid inside a cubical container of side 1 m. If the pressures inside and outside the container are as shown in the figure, what is the net force on one wall of the container?

#### Diagram Explanation:
- The diagram illustrates a transparent cube with fluid inside it.
- The side length of the cube is 1 meter.
- Inside the cube, the pressure (\( P_{in} \)) is 5 atmospheres (atm).
- Outside the cube, the pressure (\( P_{out} \)) is 1 atmosphere (atm).

#### Question:
Calculate the net force acting on one wall of the container.

#### Choices:
a) \( 3.039 \times 10^5 \) N  
b) \( 4.052 \times 10^5 \) N  
c) \( 5.065 \times 10^5 \) N  
d) \( 6.078 \times 10^5 \) N

### Detailed Solution:

1. **Conversion of Pressure Units:**
   - 1 atm = \( 1.013 \times 10^5 \) Pascals (Pa).

2. **Calculate the Pressure Difference:**
   - Pressure inside (\( P_{in} \)) in Pascals:  
     \( 5 \text{ atm} = 5 \times 1.013 \times 10^5 \text{ Pa} = 5.065 \times 10^5 \text{ Pa} \)
   - Pressure outside (\( P_{out} \)) in Pascals:  
     \( 1 \text{ atm} = 1.013 \times 10^5 \text{ Pa} \)
   - Pressure difference (\( \Delta P \)):  
     \( \Delta P = P_{in} - P_{out} \)  
     \( \Delta P = (5.065 \times 10^5 \text{ Pa}) - (1.013 \times 10^5 \text{ Pa}) \)  
     \( \Delta P = 4.052 \times 10^5 \text{ Pa} \)

3. **Calculate the Net Force:**
   - Force (\( F \)) is given by \( F = \Delta P \times A \), where \( A \)
Transcribed Image Text:### Pressure and Force in a Cubical Container #### Problem Statement: The figure below shows a fluid inside a cubical container of side 1 m. If the pressures inside and outside the container are as shown in the figure, what is the net force on one wall of the container? #### Diagram Explanation: - The diagram illustrates a transparent cube with fluid inside it. - The side length of the cube is 1 meter. - Inside the cube, the pressure (\( P_{in} \)) is 5 atmospheres (atm). - Outside the cube, the pressure (\( P_{out} \)) is 1 atmosphere (atm). #### Question: Calculate the net force acting on one wall of the container. #### Choices: a) \( 3.039 \times 10^5 \) N b) \( 4.052 \times 10^5 \) N c) \( 5.065 \times 10^5 \) N d) \( 6.078 \times 10^5 \) N ### Detailed Solution: 1. **Conversion of Pressure Units:** - 1 atm = \( 1.013 \times 10^5 \) Pascals (Pa). 2. **Calculate the Pressure Difference:** - Pressure inside (\( P_{in} \)) in Pascals: \( 5 \text{ atm} = 5 \times 1.013 \times 10^5 \text{ Pa} = 5.065 \times 10^5 \text{ Pa} \) - Pressure outside (\( P_{out} \)) in Pascals: \( 1 \text{ atm} = 1.013 \times 10^5 \text{ Pa} \) - Pressure difference (\( \Delta P \)): \( \Delta P = P_{in} - P_{out} \) \( \Delta P = (5.065 \times 10^5 \text{ Pa}) - (1.013 \times 10^5 \text{ Pa}) \) \( \Delta P = 4.052 \times 10^5 \text{ Pa} \) 3. **Calculate the Net Force:** - Force (\( F \)) is given by \( F = \Delta P \times A \), where \( A \)
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