Three point charges are arranged as shown in the figure below. Find the magnitude and direction of the electric force on the particle q = 5.30 nC at the origin. (Let 12 = 0.250 m.) magnitude N
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Given:
q=5.30
r12=0.25m
To find:
Magnitude and direction.
Step by step
Solved in 3 steps
- A dipole with –Q at the origin (0,0) and the +Q at coordinates x= 4.00 cm, y = 3.00 cm is in an Electric field, E = 4.25 V/m directed to the right, +x . (Q = 0.400 C) Draw and label a figure.A particle of charge q =3.6nC and mass m = 13µg has an initial velocity of vo =28 directly toward an infinite line charge X = 156 C. The charge q is initially a distance to = 87cm from the line charge. As the charge approaches the line it comes to a momentary stop. Determine the distance the charge is from the line when it comes to a stop (in cm). m10 nC B. A -5 nC You wish to place a charge at A, which when released will move away from the two charges shown, and then determine the speed of the charge when it gets an infinite distance away from the two charges. The rectangle is 18.4 cm high and 21.9 cm wide. In order for the charge placed at A to move to infinity, you must use an electron a proton When released, approximately which direction will the charge initially accelerate? Image an analog clock face placed at A with 12 o'clock upward. toward ---Select--- v o'clock How fast will the charge be moving when it gets an infinite distance from the two charges? m/s
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