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A ring of diameter 14 cm straddles a number line at x=0 cm such that the number line runs straight through the center point of the ring. The ring is charged to -10 nC. If you are not understanding the visual: Think of the number line as a piece of straight, uncooked spaghetti. You take a sharpie and put a black dot on the spaghetti somewhere near the middle and call that point x=0. Then you take a ring from your finger and put the spaghetti straight through the center of the hole of the ring, running the ring down the spaghetti until the ring straddles the spaghetti right at that black dot at x=0. (A)What is the magnitude of the E-field (in N/C) due to the ring at x= 1 cm? О-2550 О-3820 О-5370 О-2210 О-8.30е+03 О-993 time left... 2:04:47 (B)Now a point charge of charge -10 nC is placed at x= 11 cm. What is the magnitude of E-field (in N/C) due to this point charge at x= 1 cm? O 29300 O351o O1.90e+04 O 13500 O7830 O9.00e+03 (C)Next, a thin rod is lain lengthwise along the x-axis (so that the x-axis runs along the length of the rod. In other words it lies flat along the x axis, not perpendicular to it). The rod is 4 cm long and is lain so that its left end rests at x= -12 cm. The rod carries a charge of 22 nC. What is the magnitude of E-field (in N/C) due to this rod at x=1cm? O 25400 O35700 O6.60e+03 O 55200 O14700 O16900 (D)Next a charged disk of diameter 18 cm that is charged uniformly to a charge of 12 nC is placed so that it straddles the x-axis at x = 16 cm so that the x axis runs straight through its center (like the ring above.. except its a disk). What is the magnitude of the E-field (in N/C) at x = 1 cm due to this disk? O-12400 O-3310 O-5.70e+03 O-1480 O-3.80e+03 O-8020 (E)What is the TOTAL E-field (in N/C) at x= 1 cm (dont forget that you now have to take into account which way each of the E-fields you calculated above points keeping in mind that they all point either left or right). O 29400 O1.70e+04 O19600 O 7640 O41300 O 63800

A ring of diameter 14 cm straddles a number line at x=0 cm such that the number line runs straight through the center point of the ring. The ring is charged to -10 nC. If you are not understanding the visual: Think of the number line as a piece of straight, uncooked spaghetti. You take a sharpie and put a black dot on the spaghetti somewhere near the middle and call that point x=0. Then you take a ring from your finger and put the spaghetti straight through the center of the hole of the ring, running the ring down the spaghetti until the ring straddles the spaghetti right at that black dot at x=0. (A)What is the magnitude of the E-field (in N/C) due to the ring at x= 1 cm? О-2550 О-3820 О-5370 О-2210 О-8.30е+03 О-993 time left... 2:04:47 (B)Now a point charge of charge -10 nC is placed at x= 11 cm. What is the magnitude of E-field (in N/C) due to this point charge at x= 1 cm? O 29300 O351o O1.90e+04 O 13500 O7830 O9.00e+03 (C)Next, a thin rod is lain lengthwise along the x-axis (so that the x-axis runs along the length of the rod. In other words it lies flat along the x axis, not perpendicular to it). The rod is 4 cm long and is lain so that its left end rests at x= -12 cm. The rod carries a charge of 22 nC. What is the magnitude of E-field (in N/C) due to this rod at x=1cm? O 25400 O35700 O6.60e+03 O 55200 O14700 O16900 (D)Next a charged disk of diameter 18 cm that is charged uniformly to a charge of 12 nC is placed so that it straddles the x-axis at x = 16 cm so that the x axis runs straight through its center (like the ring above.. except its a disk). What is the magnitude of the E-field (in N/C) at x = 1 cm due to this disk? O-12400 O-3310 O-5.70e+03 O-1480 O-3.80e+03 O-8020 (E)What is the TOTAL E-field (in N/C) at x= 1 cm (dont forget that you now have to take into account which way each of the E-fields you calculated above points keeping in mind that they all point either left or right). O 29400 O1.70e+04 O19600 O 7640 O41300 O 63800

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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It would be helpful to draw a diagram for the following: A ring of diameter 14 cm straddles a number line at x=0 cm such that the number line runs straight through the center point of the ring. The ring is charged to -10 nC. If you are not understanding the visual: Think of the number line as a piece of straight, uncooked spaghetti. You take a sharpie and put a black dot on the spaghetti somewhere near the middle and call that point x=0. Then you take a ring from your finger and put the spaghetti straight through the center of the hole of the ring, running the ring down the spaghetti until the ring straddles the spaghetti right at that black dot at x=0. (A)What is the magnitude of the E-field (in N/C) due to the ring at x= 1 cm? O-2550 O-3820 O-5370 O-2210 O-8.30e+03 O-993 time left... 2:04:47 (B)Now a point charge of charge -10 nC is placed at x= 11 cm. What is the magnitude of E-field (in N/C) due to this point charge at x= 1 cm? О 29300 О3510 O1.90е+04 013500 О7830 09.00е+03 (C)Next, a thin rod is lain lengthwise along the x-axis (so that the x-axis runs along the length of the rod. In other words it lies flat along the x axis, not perpendicular to it). The rod is 4 cm long and is lain so that its left end rests at x= -12 cm. The rod carries a charge of 22 nC. What is the magnitude of E-field (in N/C) due to this rod at x=1cm? O 25400 O 35700 06.60e+03 O 55200 O14700 O16900 (D)Next a charged disk of diameter 18 cm that is charged uniformly to a charge of 12 nC is placed so that it straddles the x-axis at x = 16 cm so that the x axis runs straight through its center (like the ring above.. except its a disk). What is the magnitude of the E-field (in N/C) at x =1 cm due to this disk? О-12400 О-3310 О-5.70е+03 О-1480 С-з.80е+03 О-8020 (E)What is the TOTAL E-field (in N/C) at x= 1 cm (dont forget that you now have to take into account which way each of the E-fields you calculated above points keeping in mind that they all point either left or right). O 29400 O1.70e+04 O19600 O7640 O41300 O63800 These are the E-fields pointing along the x-axis for each of the shapes given (other than the point charge, which you should know): xQ Ering = k. (R=radius, x=how far from the center) (x² + R²)³/2 E disk = 27k o(1- (o=charge/area) (x² + R? kQ (along the x-axis) z(z + L) E rod = (L=length, z=how far from the end of the rod)
Transcribed Image Text:It would be helpful to draw a diagram for the following: A ring of diameter 14 cm straddles a number line at x=0 cm such that the number line runs straight through the center point of the ring. The ring is charged to -10 nC. If you are not understanding the visual: Think of the number line as a piece of straight, uncooked spaghetti. You take a sharpie and put a black dot on the spaghetti somewhere near the middle and call that point x=0. Then you take a ring from your finger and put the spaghetti straight through the center of the hole of the ring, running the ring down the spaghetti until the ring straddles the spaghetti right at that black dot at x=0. (A)What is the magnitude of the E-field (in N/C) due to the ring at x= 1 cm? O-2550 O-3820 O-5370 O-2210 O-8.30e+03 O-993 time left... 2:04:47 (B)Now a point charge of charge -10 nC is placed at x= 11 cm. What is the magnitude of E-field (in N/C) due to this point charge at x= 1 cm? О 29300 О3510 O1.90е+04 013500 О7830 09.00е+03 (C)Next, a thin rod is lain lengthwise along the x-axis (so that the x-axis runs along the length of the rod. In other words it lies flat along the x axis, not perpendicular to it). The rod is 4 cm long and is lain so that its left end rests at x= -12 cm. The rod carries a charge of 22 nC. What is the magnitude of E-field (in N/C) due to this rod at x=1cm? O 25400 O 35700 06.60e+03 O 55200 O14700 O16900 (D)Next a charged disk of diameter 18 cm that is charged uniformly to a charge of 12 nC is placed so that it straddles the x-axis at x = 16 cm so that the x axis runs straight through its center (like the ring above.. except its a disk). What is the magnitude of the E-field (in N/C) at x =1 cm due to this disk? О-12400 О-3310 О-5.70е+03 О-1480 С-з.80е+03 О-8020 (E)What is the TOTAL E-field (in N/C) at x= 1 cm (dont forget that you now have to take into account which way each of the E-fields you calculated above points keeping in mind that they all point either left or right). O 29400 O1.70e+04 O19600 O7640 O41300 O63800 These are the E-fields pointing along the x-axis for each of the shapes given (other than the point charge, which you should know): xQ Ering = k. (R=radius, x=how far from the center) (x² + R²)³/2 E disk = 27k o(1- (o=charge/area) (x² + R? kQ (along the x-axis) z(z + L) E rod = (L=length, z=how far from the end of the rod)
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