A particle of charge q =3.6nC and mass m = 13μg has an initial velocity of vo =28 directly toward an infinite line charge λ =156 C. The charge qis initially a distance to = 87cm from the line charge. As the charge approaches the line it comes to a momentary stop. Determine the distance the charge is from the line when it comes to a stop (in cm). m

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Chapter1: Units, Trigonometry. And Vectors
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A particle of charge \( q = 3.6 \, \text{nC} \) and mass \( m = 13 \, \mu \text{g} \) has an initial velocity of \( v_0 = 28 \, \frac{m}{s} \) directly toward an infinite line charge \( \lambda = 156 \, \frac{\text{nC}}{m} \). The charge \( q \) is initially a distance \( r_0 = 87 \, \text{cm} \) from the line charge. As the charge approaches the line, it comes to a momentary stop. Determine the distance the charge is from the line when it comes to a stop (in cm).

[Note: There are no graphs or diagrams in the image.]
Transcribed Image Text:A particle of charge \( q = 3.6 \, \text{nC} \) and mass \( m = 13 \, \mu \text{g} \) has an initial velocity of \( v_0 = 28 \, \frac{m}{s} \) directly toward an infinite line charge \( \lambda = 156 \, \frac{\text{nC}}{m} \). The charge \( q \) is initially a distance \( r_0 = 87 \, \text{cm} \) from the line charge. As the charge approaches the line, it comes to a momentary stop. Determine the distance the charge is from the line when it comes to a stop (in cm). [Note: There are no graphs or diagrams in the image.]
Expert Solution
Step 1

Given that

the charge of the particle is q=3.6nC=3.6×10-9C

and the mass of the particle is m=13μg=13×10-9kg

the charge density of the infinite line charge is λ=156nCm

the initial position of the particle is ro=87cm=0.87m

the initial velocity of the particle is vo=28m/s

And the final velocity of the particle is v=0m/s

 

Since the electric force due to the line charge on the particle at distance r is 

F=2kqλr

where k is the coulomb's constant

k=9×10-9N.m2/C2

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