tere is a side view of a 3-dimensional rectangular box. The ong (horizontal) side measures 10 cm, and the ends are quare with sides measuring 2 cm. There is a uniform ertical electric field of 500 V/m below the box, and a aniform vertical electric field of 1000 V/m above the box. tow much charge is in the box? a.-4.43 x 10 "c -b. 2.66 x 10 "c c. 4.43 x 10 IIC d. -2.66 x 10 "c Pe. 8.85 x 10 f.-8.85 x 10

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Chapter1: Units, Trigonometry. And Vectors
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**Title:** Determining the Charge in a Rectangular Box within an Electric Field

**Description:**

This diagram depicts a side view of a 3-dimensional rectangular box. The illustration highlights several key dimensions and conditions:

- **Box Dimensions:**
  - The long (horizontal) side is 10 cm.
  - The ends are square, each with sides measuring 2 cm.

- **Electric Fields:**
  - Below the box, there is a uniform vertical electric field of 500 V/m.
  - Above the box, there is a uniform vertical electric field of 1000 V/m.

**Problem Statement:**

The task is to calculate the amount of charge contained in the box. Several answer options are provided:

- (a) \(4.43 \times 10^{-11}\) C
- (b) \(2.66 \times 10^{-11}\) C
- (c) \(-4.43 \times 10^{-11}\) C
- (d) \(-2.66 \times 10^{-11}\) C
- (e) \(8.85 \times 10^{-12}\) C
- (f) \(-8.85 \times 10^{-12}\) C

**Diagram Explanation:**

The diagram includes arrows indicating the direction of the electric fields. The arrows below the box represent the field pointing upwards at 500 V/m, while the arrows above show the field pointing upwards at 1000 V/m. These fields affect how the charge within the box is determined.
Transcribed Image Text:**Title:** Determining the Charge in a Rectangular Box within an Electric Field **Description:** This diagram depicts a side view of a 3-dimensional rectangular box. The illustration highlights several key dimensions and conditions: - **Box Dimensions:** - The long (horizontal) side is 10 cm. - The ends are square, each with sides measuring 2 cm. - **Electric Fields:** - Below the box, there is a uniform vertical electric field of 500 V/m. - Above the box, there is a uniform vertical electric field of 1000 V/m. **Problem Statement:** The task is to calculate the amount of charge contained in the box. Several answer options are provided: - (a) \(4.43 \times 10^{-11}\) C - (b) \(2.66 \times 10^{-11}\) C - (c) \(-4.43 \times 10^{-11}\) C - (d) \(-2.66 \times 10^{-11}\) C - (e) \(8.85 \times 10^{-12}\) C - (f) \(-8.85 \times 10^{-12}\) C **Diagram Explanation:** The diagram includes arrows indicating the direction of the electric fields. The arrows below the box represent the field pointing upwards at 500 V/m, while the arrows above show the field pointing upwards at 1000 V/m. These fields affect how the charge within the box is determined.
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