Three-phase, 50 Hz 34500/10500 delta-star connected transformer, single phase visible on high voltage (primary) windings side equivalent circuit parameters are given below. Each of the low voltage (secondary) windings of this transformer When a 7.5 ohm star connected resistive load is connected and the rated voltage is applied to the high voltage windings find transformer efficiency. Total iron losses of three phases will be taken as 85000 W. Primer sargı iç direnci (R1) Primer sargı kaçak reaktansı (X1) Sekonder sargı iç direnci (primere taşınmış) (R2') Sekonder sargı kaçak reaktansı (primere taşınmış) (X2') 1,25 2 1,85 2 1,25 2 1,82 2

Three-phase, 50 Hz 34500/10500 delta-star connected transformer, single phase visible on high voltage (primary) windings side equivalent circuit parameters are given below. Each of the low voltage (secondary) windings of this transformer When a 7.5 ohm star connected resistive load is connected and the rated voltage is applied to the high voltage windings find transformer efficiency. Total iron losses of three phases will be taken as 85000 W. Primer sargı iç direnci (R1) Primer sargı kaçak reaktansı (X1) Sekonder sargı iç direnci (primere taşınmış) (R2') Sekonder sargı kaçak reaktansı (primere taşınmış) (X2') 1,25 2 1,85 2 1,25 2 1,82 2

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

The losses found in a transformer
A 2300V to 230V step down transformer is rated at 750 KVA and 60 Hz. Its winding have the following resistances and inductances: Re' =0.093 ohm Re" = 0.00093 ohm Xe' =0.280 ohm Xe" =0.0028 ohm The transformer is operating on rated load.
formula for determining the power of a single-phase transformer
Due to the increase in load, what change you saw in the transformer’s output power and voltage regulation?
B- the eddy current losses of 400V, 50 Hz transformer is 1600W and the total iron losses i 2500W. calculate the iron losses at 200V, 25 Hz.
Current transformer has Select one: O a. No relation between primary windings and its secondary windings O b. More secondary windings than its primary windings O C. Primary windings equal to secondary windings O d. More primary windings than its secondary windings
b) The parameters of the transformer equivalent circuit are given bellow, Primary =1290. Secondary winding turns =130. The resistance of the primary winding =0.2 O. The resistance of the secondary winding =0.06 N. The leakage reactance of the primary winding =1.47 Q. The leakage reactance of the secondary winding =0.07 Q. using the above parameter values, referred to the primary winding, determine (a) Equivalent resistance, (b) Equivalent reactance, (c) Equivalent impedance and (d) The phase angle of the impedance.
All information about current transformer and voltage transformer in protection system
What's The procedure of open circuit test on single phase transformer?
In a single phase transformer when all parameter is shifted to primary side value of primary side resistance is 0.5 ohm and resistance which is shifted from secondary to primary is also 0.5 ohm. If full load current in primary side is 20(A) what is total copper loss in transformer.