Three impedances of 5 + j 12, 8j7 and 3 - j12 ohms are connected in star to red, yellow and blue lines of a 5000 V, 3- phase, 4 - wire supply. The phase sequence is RYB. Calculate the line currents.
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- Problem 1 - Series en Parallel AC networks [19] Look at the circuit in Figure 1 and determine the following: (a) Total Admittance. (b) Total Impedance. (c) Total Current (l:). (d) Current (I1) through impedance Z2. (e) Current (12) through impedance Z3. (f) Current (I3) through impedance Z4. (g) Is this an inductive or capacitive circuit? A. B Zs 220V;50HZ Figure 1 (h) Voltage across Z1. (i) Voltage across A and B. G) Voltage across Zs. Z1 = 3 + j5 ohm Z2 = 10 + jo ohm Z3 = 5 + j15 ohm Z4 = 10 – j30 ohm Zs = 20 – j30 ohm Admittance and Impedance in rectangular notation. All currents and voltage in polar notation. Take voltage as reference.2. The following information is given in connection with the two phase three wire circuit of the figure. EBA = 240 volts Load "NA" is an impedance of (10 +j6) Load "BN" is an impedance of (7-j12) Q Load "BA" takes a current of 14 A at a leading p.f. of 0.95 Calculate a). Current INA and IBN. b). Neutral current IN. c). Line circuits IA and IB. d). The total power. IB IN LOAD BN LOAD NA 0000 IA B IBN N INA IBA LOAD BAOne advantages of load balancing is that each phase conductor carries the ? current value
- 1. How do you measure three phase line currents by using two current transformers? Draw the connection scheme.Three single-phase distribution transformers, each rated for 18 kVA, 20000/220 volts, are connected in a Dy three-phase bank. For convenience, at the factory, the OCT and the SCT were per- formed as per standards with the whole three-phase bank already connected and the measured values were as follows: Vline 381.051V, line 1.78436A, P30 = 372.414 W. Vline = 5656.85 V, Iline = 1.55885 A, P30 = 2160 W. Three phase bank of single phase transformer on a utility pole. 37.5 K (a) Find the single phase equivalent circuit referred to the low volt- age side. (b) Find the transformer regulation at the rated load and voltage and a power factor of 0.45 lagging (Neglect the excitation current). (c) Using the "load" model, what is the approximate transformer- bank's efficiency, n, under these conditions of load? (a) R2 X=2 Rsc=mXsc = mS (b) Vreg= (c) n = %In the circuit of figure shown in the next slide, threeimpedances are 12 – j10 ohms, 10 + j20 ohms, and 15 + j0ohms, connected between conductors a, b, c and the neutral“n” of a balanced 230 volts, 60 hertz, 3 phase, 4 wire, ABCsystem. Using Van as the reference vector, determine:a. Current in each impedanceb. Neutral current Inc. Readings of wattmeters W1, W2, & W3d. Power in each impedance ..
- 3-phase 50-kVA 31,5/0,4-KVLL distribution transformers are connected in A-Y. Open-circuit test was performed on the high-voltage side of this transformer bank, and the following data were recorded: Vline,oc=480 V, Iline,oc=4.10 A, Poc = 945 W Short-circuit test was performed on the low-voltage side of this transformer bank, and the following data were recorded: Vline,sc = 808 V, Iline,sc = 3.11 A, Psc = 912 W (a) Find the voltage regulation of this transformer bank at the rated load and 0.85 power factor lag. (b) Draw a phasor diagram of this transformer at 0.85 power factor leading. A 20 Hp, 440-V, 0.85-PF-lagging Y-connected synchronous motor has an armature resistance of 0.22 2 and a synchronous reactance of 3.0 2. Its efficiency at full load is 92% (1 Hp=746 watt). (a) What is the input power to the motor at rated conditions? (b) What is the line current of the motor at rated conditions? (c) What is the internal generated voltage EA of this motor at rated conditions? A 3-phase…A current is measured at the neutral ground of a star load, of equal impedances in all three phases. Which of the following conditions is NOT possible?A) The currents in the three phases are equal in magnitude and angle.B)One phase of the supply conductors was left in open circuit.C) The line-to-neutral voltages in the load are equal in magnitude and with 120° phase shifts between them.D) None of the abovea)Why are transformers generally connected in parallel at a substation?b)What conditions must be met for two transformers to be paralleled?c)Draw the phase relationship and connection diagram for Dd0 connection andYy6
- H.W 6: For the systom shown, determeine the fauttt level and short cerint current for a 3-phase fault at the of The linee. middle ofone のC) Vo.2 P.u t02p.u ikV 132 ICV =110 p.u 132KV Assume all reactances of generatos and transfe ona 10% u kV at aen's. on common base, Sb- 50 MVA,Consider the system shown in Figure 1. Assume the load voltage (VL) is 4720 V and the load consumption is 80 kVA at 0.85 lagging power factor. The line impedance (Zline) is 4.6+j8.5 2. The parameters of the 14,400/4800-V single-phase transformer referred to the secondary are: Req=0.95 , Xeq = 1.74 , Re = 48.5 kn, and Xm = 31.1 k. vp avs 4.6 +19.52 Zline Vs ~ P a:1 ele rmis alf Reais leee V₂ zí S Figure 1: System for Q1 I wad a) Find the current of the load. b) Find the primary and secondary voltages of the ideal transformer. nuomo I un cucc + Bline Xeq,s 1 V₂² 95, 74-32 1. VL 4720 Ponerlosture -> Pont IL = V₂ -V₂ ZineConsider the three single-phase two-winding transformers shown in Figure 3.37. The high-voltage windings are connected in Y. (a) For the low-voltage side, connect the windings in , place the polarity marks, and label the terminals a, b, and c in accordance with the American standard. (b) Relabel the terminals a, b, and c such that VAN is 90 out of phase with Va for positive sequence.