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Three Impedances each of (11 – j20)Ω are connected in mesh across a three-phase 410V ac supply. Determine the phase current, line current, active power, reactive power drawn from the supply. Also, draw the Phasor diagram for the mesh connection and mark the Line current, phase current line voltage, and phase angle between phase current and phase voltage.  phase current (Ip) = Line current = real power=

Three Impedances each of (11 – j20)Ω are connected in mesh across a three-phase 410V ac supply. Determine the phase current, line current, active power, reactive power drawn from the supply. Also, draw the Phasor diagram for the mesh connection and mark the Line current, phase current line voltage, and phase angle between phase current and phase voltage.  phase current (Ip) = Line current = real power=

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Three Impedances each of (11 – j20)Ω are connected in mesh across a three-phase 410V ac supply. Determine the phase current, line current, active power, reactive power drawn from the supply. Also, draw the Phasor diagram for the mesh connection and mark the Line current, phase current line voltage, and phase angle between phase current and phase voltage. 

phase current (Ip) =

Line current =

real power=

reactive power=

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