i need the answer quickly H.W.(1): For the three-phase A –A system in Figure shown, Find thephase and line currents. Draw phasordiagram.E 120 Vo3phane, 3wireAconected a peneratorPhae oquence ACREea- 120 V2Ege - 120 V Z4,(Answer: IAB = 33.945° A, Isc = 33.94165° A, ICA = 33.92 - 75 A, I = 58.82475°A, IB = 58.824195º A, Ic = 58.824- 45° A]%3DH.W.(2): For the A-connectedload in Figure, find the linevoltages, phase currents andline currents. Draw the phasordiagram.I K- 16 kV 20he = 16 AV 2-120= 16 kV Z+1201022000.3 kIsECA +10020 1Enc03 k0.3 K2I K[Answer:](a) L = 15.33 AZ-73.30°,I = 15.33 A Z-193.30°,La = 15.33 A Z46.7°10 120 f1(b) Ia = 26.55 AL-103.30°, (c) EAB = 17.01 kV2-0.59°,Ig = 26.55 A Z136.70°,Ia = 26.55 A Z16.70°%3DEgc = 17.01 kV -120.59°,Eca = 17.01 kV Z119.41°%3D%3D%3D

Since you have asked multiple questions in a single request, we will be answering only the 1st…

three-phase A system in Figure shown, Find the phase and line currents. Draw phasor diagram. K 120 Vo 3phase, mire Aneted a penerator Phe opence ACH KA- 120 V Ea 120 V, [Answer: IAB = 33.945° A, Isc = 33.94165° A, ICA = 33.92 - 75 A, I = 58.82475° A. In = 58.82/195° A. Ic = 58.824 - 45° A1 %3D

three-phase A system in Figure shown, Find the phase and line currents. Draw phasor diagram. K 120 Vo 3phase, mire Aneted a penerator Phe opence ACH KA- 120 V Ea 120 V, [Answer: IAB = 33.945° A, Isc = 33.94165° A, ICA = 33.92 - 75 A, I = 58.82475° A. In = 58.82/195° A. Ic = 58.824 - 45° A1 %3D

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Question

i need the answer quickly

H.W.(1): For the three-phase A –
A system in Figure shown, Find the
phase and line currents. Draw phasor
diagram.
E 120 Vo
3phane, 3wire
Aconected a penerator
Phae oquence ACR
Eea- 120 V2
Ege - 120 V Z4,
(Answer: IAB = 33.945° A, Isc = 33.94165° A, ICA = 33.92 - 75 A, I = 58.82475°
A, IB = 58.824195º A, Ic = 58.824- 45° A]
%3D
H.W.(2): For the A-connected
load in Figure, find the line
voltages, phase currents and
line currents. Draw the phasor
diagram.
I K
- 16 kV 20
he = 16 AV 2-120
= 16 kV Z+120
102
200
0.3 k
Is
ECA +
100
20 1
Enc
03 k
0.3 K2
I K
[Answer:]
(a) L = 15.33 AZ-73.30°,
I = 15.33 A Z-193.30°,
La = 15.33 A Z46.7°
10 1
20 f1
(b) Ia = 26.55 AL-103.30°, (c) EAB = 17.01 kV2-0.59°,
Ig = 26.55 A Z136.70°,
Ia = 26.55 A Z16.70°
%3D
Egc = 17.01 kV -120.59°,
Eca = 17.01 kV Z119.41°
%3D
%3D
%3D

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