Three different methods for assembling a product were proposed by an industrial engineer. To investigate the number of units assembled correctly with each method, 39 employees were randomly selected and randomly assigned to the three proposed methods in such a way that each method was used by 13 workers. The number of units assembled correctly was recorded, and the analysis of variance procedure was applied to the resulting data set. The following results were obtained: SST = 13,220; SSTR = 4,520. (a) Set up the ANOVA table for this problem. (Round your values for MSE and F to two decimal places, and your p-value to four decimal places.) Source of Variation Sum of Squares Degrees of Freedom Mean Square F p-value Treatments           Error           Total         B. Find the value of the test statistic. (Round your answer to two decimal places.)   C. Find the p-value. (Round your answer to four decimal places.) p-value =

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A: According to the given information, We have Probability = 80%=0.80Sample size = 40

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Q: For a two-factor ANOVA, if SSwithin treatments = 86, SSbetween treatments = 80, SSbetween subjects =…

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A: Solution:

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A:

Q: MSA agrees to purchase the products of an Enterprise if the produced items do not have variance of…

A: Given data, 18.63, 18.43, 18.34, 18.58, 18.64, 18.37, 18.43, 18.63, 18.22,18.57, 18.34, 18.12,…

Q: If a data set produces SSR = 300 and SSE = 200, then the coefficient of determination is

A: SSR = 300 SSE = 200 coefficient of determination(R2) = ? SST = SSE+SSR = 200+300 = 500

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Q: compute the range, variance, and standard deviation for the two samples

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Q: The formula for total variance (SST) is

A: Solution:-

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A: SS for one sample =60 SS for second sample =48

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A:

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A: Hello! As you have posted more than 3 sub parts, we are answering the first 3 sub-parts.  In case…

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Q: 6) Suppose that you score 79 on Exam 3. If the average score is 85, and the variance is 23.04, your…

A:

Q: Given the data: 1, 4, 3, 5, 4, Its Variance value is 2 3 4

A: by using given data(x);  1,4,3,5,4 x x2 1 1 4 16 3 9 5 25 4 16 ∑x=17 ∑x2=67