Three different methods for assembling a product were proposed by an industrial engineer. To investigate the number of units assembled correctly with each method, 30 employees were randomlyselected and randomly assigned to the three proposed methods in such a way that each method was used by 10 workers. The number of units assembled correctly was recorded, and the analysis ofvariance procedure was applied to the resulting data set. The following results were obtained: SST =10,910; SSTR4,560.(a) Set up the ANOVA table for this problem. (Round your values for MSE and F to two decimal places, and your p-value to four decimal places.)SourceSumMeanDegreesof FreedomFp-valueof Variationof SquaresSquareTreatmentsErrorTotal(b) Use a = 0.05 to test for any significant difference in the means for the three assembly methods.State the null and alternative hypotheses.Ho: Not all the population means are equal.Hai H1 = H2 = H3%DHoi H1 = H2 = H3H: Not all the population means are equal.Ho: At least two of the population means are equal.H: At least two of the population means are different.Hoi H1# Hz # H3Ha: H1 = H2 = H3Hoi H1 = H2 = H3Hai H1+ H3Find the value of the test statistic. (Round your answer to two decimal places.)Find the p-value. (Round your answer to four decimal places.)p-value State your conclusion.Do not reject Ho. There is not sufficient evidence to conclude that the means of the three assembly methods are not equal.Reject Ho. There is sufficient evidence to conclude that the means of the three assembly methods are not equal.Reject Ho. There is not sufficient evidence to conclude that the means of the three assembly methods are not equal.Do not reject Ho: There is sufficient evidence to conclude that the means of the three assembly methods are not equal.

A random sample of 30 employees were randomly selected for each method to investigate the number of…

Three different methods for assembling a product were proposed by an industrial engineer. To investigate the number of units assembled correctly with each method, 30 employees were randomly selected and randomly assigned to the three proposed methods in such a way that each method was used by 10 workers. The number of units assembled correctly was recorded, and the analysis of variance procedure was applied to the resulting data set. The following results were obtained: SST = 10,910; SSTR = 4,560. (a) Set up the ANOVA table for this problem. (Round your values for MSE and F to two decimal places, and your p-value to four decimal places.) Source Sum Degrees of Freedom Mean F p-value of Variation of Squares Square Treatments Error Total (b) Use a = 0.05 to test for any significant difference in the means for the three assembly methods. State the null and alternative hypotheses. O Ho: Not all the population means are equal. Hi H1 = H2 = H3 O Ho: H1 = H2 = H3 H: Not all the population means are equal.

Three different methods for assembling a product were proposed by an industrial engineer. To investigate the number of units assembled correctly with each method, 30 employees were randomly selected and randomly assigned to the three proposed methods in such a way that each method was used by 10 workers. The number of units assembled correctly was recorded, and the analysis of variance procedure was applied to the resulting data set. The following results were obtained: SST = 10,910; SSTR = 4,560. (a) Set up the ANOVA table for this problem. (Round your values for MSE and F to two decimal places, and your p-value to four decimal places.) Source Sum Degrees of Freedom Mean F p-value of Variation of Squares Square Treatments Error Total (b) Use a = 0.05 to test for any significant difference in the means for the three assembly methods. State the null and alternative hypotheses. O Ho: Not all the population means are equal. Hi H1 = H2 = H3 O Ho: H1 = H2 = H3 H: Not all the population means are equal.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Concept explainers

Continuous Probability Distributions

Probability distributions are of two types, which are continuous probability distributions and discrete probability distributions. A continuous probability distribution contains an infinite number of values. For example, if time is infinite: you could count from 0 to a trillion seconds, billion seconds, so on indefinitely. A discrete probability distribution consists of only a countable set of possible values.

Normal Distribution

Suppose we had to design a bathroom weighing scale, how would we decide what should be the range of the weighing machine? Would we take the highest recorded human weight in history and use that as the upper limit for our weighing scale? This may not be a great idea as the sensitivity of the scale would get reduced if the range is too large. At the same time, if we keep the upper limit too low, it may not be usable for a large percentage of the population!

Question

100%

Three different methods for assembling a product were proposed by an industrial engineer. To investigate the number of units assembled correctly with each method, 30 employees were randomly
selected and randomly assigned to the three proposed methods in such a way that each method was used by 10 workers. The number of units assembled correctly was recorded, and the analysis of
variance procedure was applied to the resulting data set. The following results were obtained: SST =
10,910; SSTR
4,560.
(a) Set up the ANOVA table for this problem. (Round your values for MSE and F to two decimal places, and your p-value to four decimal places.)
Source
Sum
Mean
Degrees
of Freedom
F
p-value
of Variation
of Squares
Square
Treatments
Error
Total
(b) Use a = 0.05 to test for any significant difference in the means for the three assembly methods.
State the null and alternative hypotheses.
Ho: Not all the population means are equal.
Hai H1 = H2 = H3
%D
Hoi H1 = H2 = H3
H: Not all the population means are equal.
Ho: At least two of the population means are equal.
H: At least two of the population means are different.
Hoi H1# Hz # H3
Ha: H1 = H2 = H3
Hoi H1 = H2 = H3
Hai H1
+ H3
Find the value of the test statistic. (Round your answer to two decimal places.)
Find the p-value. (Round your answer to four decimal places.)
p-value

State your conclusion.
Do not reject Ho. There is not sufficient evidence to conclude that the means of the three assembly methods are not equal.
Reject Ho. There is sufficient evidence to conclude that the means of the three assembly methods are not equal.
Reject Ho. There is not sufficient evidence to conclude that the means of the three assembly methods are not equal.
Do not reject Ho: There is sufficient evidence to conclude that the means of the three assembly methods are not equal.

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