this was a reaction between aluminum and copper (ii) sulfate. trial m(Al), g 0.250M CuSO4, mL m(Cu), g n(Al) n(Cu) ratio n(Cu)/n(Al) drops 6M HCl % yield 1 0.1 25 0.33 5 I need help to calculate: moles of aluminum (n(Al)) moles of copper (n(Cu)) the ratio of molex of copper
this was a reaction between aluminum and copper (ii) sulfate. trial m(Al), g 0.250M CuSO4, mL m(Cu), g n(Al) n(Cu) ratio n(Cu)/n(Al) drops 6M HCl % yield 1 0.1 25 0.33 5 I need help to calculate: moles of aluminum (n(Al)) moles of copper (n(Cu)) the ratio of molex of copper
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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this was a reaction between aluminum and copper (ii) sulfate.
trial | m(Al), g | 0.250M CuSO4, mL | m(Cu), g | n(Al) | n(Cu) | ratio n(Cu)/n(Al) | drops 6M HCl | % yield |
1 | 0.1 | 25 | 0.33 | 5 |
I need help to calculate:
moles of aluminum (n(Al))
moles of copper (n(Cu))
the ratio of molex of copper and alumminun (n(Cu)) / (n(Al))
and the percent yield by the reaction.
Please note that the HCl drops were used as a catalyst, so they are not part of the reaction.
I really appreciate any help you can provide.
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