This question has 2 parts:  9.762 g of a non-volatile solute is dissolved in 175.0 g of water.The solute does not react with water nor dissociate in solution.Assume that the resulting solution displays ideal Raoult's law behaviour.At 25°C the vapour pressure of the solution is 23.405 torr.The vapour pressure of pure water at 25°C is 23.756 torr.Calculate the molar mass of the solute (g/mol).    Now suppose, instead, that 9.762 g of a volatile solute is dissolved in 175.0 g of water.This solute also does not react with water nor dissociate in solution.The pure solute displays, at 25°C, a vapour pressure of 2.376 torr.Again, assume an ideal solution.If, at 25°C the vapour pressure of this solution is also 23.405 torr.Calculate the molar mass of this volatile solute.

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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This question has 2 parts: 

  1. 9.762 g of a non-volatile solute is dissolved in 175.0 g of water.
    The solute does not react with water nor dissociate in solution.
    Assume that the resulting solution displays ideal Raoult's law behaviour.
    At 25°C the vapour pressure of the solution is 23.405 torr.
    The vapour pressure of pure water at 25°C is 23.756 torr.
    Calculate the molar mass of the solute (g/mol). 

 

  1. Now suppose, instead, that 9.762 g of a volatile solute is dissolved in 175.0 g of water.
    This solute also does not react with water nor dissociate in solution.
    The pure solute displays, at 25°C, a vapour pressure of 2.376 torr.
    Again, assume an ideal solution.
    If, at 25°C the vapour pressure of this solution is also 23.405 torr.
    Calculate the molar mass of this volatile solute.

 

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