5.758 g of a non-volatile solute is dissolved in 210.0 g of water. The solute does not react with water nor dissociate in solution. Assume that the resulting solution displays ideal Raoult's law behaviour. At 70°C the vapour pressure of the solution is 230.70 torr. The vapour pressure of pure water at 70°C is 233.70 torr. Calculate the molar mass of the solute (g/mol). Submit Answer Tries 0/99

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Raoult’s Law; I got the mole fraction but I don’t know how to calculate the mass of solvent.
5.758 g of a non-volatile solute is dissolved in 210.0 g of water.
The solute does not react with water nor dissociate in solution.
Assume that the resulting solution displays ideal Raoult's law behaviour.
At 70°C the vapour pressure of the solution is 230.70 torr.
The vapour pressure of pure water at 70°C is 233.70 torr.
Calculate the molar mass of the solute (g/mol).
Submit Answer
Tries 0/99
Transcribed Image Text:5.758 g of a non-volatile solute is dissolved in 210.0 g of water. The solute does not react with water nor dissociate in solution. Assume that the resulting solution displays ideal Raoult's law behaviour. At 70°C the vapour pressure of the solution is 230.70 torr. The vapour pressure of pure water at 70°C is 233.70 torr. Calculate the molar mass of the solute (g/mol). Submit Answer Tries 0/99
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