A certain dilute solution has an osmotic pressure of 11.1 atm at 25°C. Calculate the difference between the chemical potential of the solvent in the solution and that of pure water. Assume that the density is the same as that of water at 25°C, 0.99705 g-cm-3. (Hint: Express the chemical potential in terms of mole fraction, x1, and rewrite the osmotic pressure equation as NV = n2RT, where n2 is the number of moles of the solute and V = 1.00 L.) %3D

A certain dilute solution has an osmotic pressure of 11.1 atm at 25°C. Calculate the difference between the chemical potential of the solvent in the solution and that of pure water. Assume that the density is the same as that of water at 25°C, 0.99705 g-cm-3. (Hint: Express the chemical potential in terms of mole fraction, x1, and rewrite the osmotic pressure equation as NV = n2RT, where n2 is the number of moles of the solute and V = 1.00 L.) %3D

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

The freezing-point depression constant of chloroform is 4.70 kg K mole. When 10.52 g of a non-volatile solute are dissolved in 150.0 g of chloroform, the solution freezes exactly 2.39 °C below the normal freezing-point of chloroform. What is the molecular weight of the solute?.
Given that the vapor pressure of water is 17.54 Torr at 20 °C, calculate the vapor-pressure lowering, AP, of an aqueous solution that is 2.20 m in sucrose (C₁2H₂2O11). ΔΡ = 0.669 Calculate the vapor-pressure lowering, AP, of an aqueous solution that is 2.20 m in calcium chloride. Assume 100% dissociation for electrolytes. ΔΡ = 1.999 Incorrect Torr Torr
A polymer of large molar mass is dissolved in the organic solvent dimethylformamide (C3H7NO) at 25 °C, and the resulting solution rises to a final height of 10.8 cm above the level of the pure solvent, as solvent molecules pass through a semipermeable membrane into the solution. If the solution contains 3.80 g polymer per liter, calculate the molar mass of the polymer. Take the density of the solution to be 0.944 g cm-³. Molar mass polymer = g mol-1
2. A and B form an ideal solution. At a total pressure of 0.90 bar, Xa(1)=0.65, XA(g) = 0.45. Using this information, calculate the vapor pressures of pure A and pure B.
Osmotic pressures are often reported in units of atmospheres or mm Hg. The latter impliesthat the height of a column of liquid can be used as a measure of pressure. This is, in fact, thebasis of the torricellian barometer from which the units of “torr” come. The pressure, P, isrelated to the height of the column by:P = ρghwhere ρ is the density of the liquid, g is the acceleration due to gravity and h is the height. Whatwill be the height (in mm) of a column of aqueous solution with a density of 0.9987 g/mL, if theosmotic pressure of the solution at 25 °C is 1.4 mm Hg? The density of mercury at thistemperature is 13.8 g/mL
The freezing point of CCl4 was lowered by 0.52 K when 50 grams of a chemical were added to the solvent. Calculate the compound's molar mass. Kf of tetrachloromethane are equal to 30 kilograms per mole.
A semi-permeable membrane separates the contents of cell. The concentration of sodium ions is 2.1 L.atm mol mol K.mol outside of the cell and 2.5 inside of the cell. The ideal gas constant R= 8.206 x 10 -2 L L and room temperature is about 20°C or 293 K. (a) Determine the osmotic pressure (in atm) and the tonicity of the solution surrounding a cell with radius of 0.013 mm at room temperature. П= (b) The solution surrounding the cell is O Hypotonic O Hypertonic O Isotonic atm
1-propanol (n-propanol) and 2-propanol (isopropanol) form ideal solutions in all proportions. Calculate the partial pressure and the mole fraction (y) of the vapor phase of each component in equilibrium with each of the given solutions at 25 °C. Pprop=20.9 Torr and Piso = 45.2 Torr at 25 °C. A solution with a mole fraction of Xprop = 0.238. Pprop= Piso = yprop= Viso = A solution with a mole fraction of Xprop = 0.476. Pprop= Piso = yprop= Viso = A solution with a mole fraction of Xprop = 0.714. Pprop= Piso = yprop= Viso = Torr Torr Torr Torr Torr Torr
The mole fraction of sodium chloride, NaCl, in a saturated aqueous solution is 0,220. What is the molarity (molar concentration) of this solution if it has a density of 1,150 g.cm–3?