This question comes from Probability and Statistics for Engineering and the Sciences 9th Ed. by Devore, Jay Can you explain what a continuity correction is and how it is calculated? Also can you explain why .5 was chosen for this particular problem? Will it always be subtracted from one end and added to the other? Thank you for your time.

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This question comes from Probability and Statistics for Engineering and the Sciences 9th Ed. by Devore, Jay

Can you explain what a continuity correction is and how it is calculated?

Also can you explain why .5 was chosen for this particular problem?

Will it always be subtracted from one end and added to the other?

Thank you for your time.

- Probability and Statistics for Engineer...
< Chapter 5.4, Problem 55E >
Get live help whenever you need from online tutors! Try bartleby tutor today >
The random variable X is originally discrete in nature. The
approximate distribution of Xis normal, which is continuous in
nature. As a discrete variable is being approximated by a
continuous variable, a continuity correction is made by subtracting
0.5 from the lower limit 35 and adding 0.5 to the upper limit 70.
Thus,
P (35 < X < 70) z P (34.5 < X < 70.5)
P( < s 05) (by standardizing)
34.5-и
X-u
70.5-u
-( szs )
=r(zs ) -"(25-)
34.5-50
70.5-50
= P
/50
/50
20.5
15.5
–P(Z<
V50
— Ф (2.90) — Ф(-2.19)
From Table A.3, "Standard Normal Curve Areas",
Transcribed Image Text:- Probability and Statistics for Engineer... < Chapter 5.4, Problem 55E > Get live help whenever you need from online tutors! Try bartleby tutor today > The random variable X is originally discrete in nature. The approximate distribution of Xis normal, which is continuous in nature. As a discrete variable is being approximated by a continuous variable, a continuity correction is made by subtracting 0.5 from the lower limit 35 and adding 0.5 to the upper limit 70. Thus, P (35 < X < 70) z P (34.5 < X < 70.5) P( < s 05) (by standardizing) 34.5-и X-u 70.5-u -( szs ) =r(zs ) -"(25-) 34.5-50 70.5-50 = P /50 /50 20.5 15.5 –P(Z< V50 — Ф (2.90) — Ф(-2.19) From Table A.3, "Standard Normal Curve Areas",
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