4 A pond has N fish. John caught 100 fish, tagged them, and relea mem back to the pond. He then caught 50 fish, among them 10 are tagged. 1. Give an estimate of the number of fish in the pond; 2. If the pond has 400 fish (N = 400), and X is the number of fish John cau_ in the second time. Write down Sx, the range of X, and the p.m.f. of %3D 3. In the scenario of part 2; first compute the exact P(Y
4 A pond has N fish. John caught 100 fish, tagged them, and relea mem back to the pond. He then caught 50 fish, among them 10 are tagged. 1. Give an estimate of the number of fish in the pond; 2. If the pond has 400 fish (N = 400), and X is the number of fish John cau_ in the second time. Write down Sx, the range of X, and the p.m.f. of %3D 3. In the scenario of part 2; first compute the exact P(Y
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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
Transcribed Image Text:Problem 4 A pond has N fish. John caught 100 fish, tagged them, and released
them back to the pond. He then caught 50 fish, among them 10 are tagged.
1. Give an estimate of the number of fish in the pond;
2. If the pond has 400 fish (N = 400), and X is the number of fish John caught
in the second time. Write down Sx, the range of X, and the p.m.f. of X.
%3D
3. In the scenario of part 2; first compute the exact P(X = 10), and then
approximate this probability by a binomial distribution.
%3D
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