(References]Predict the sign of AS and then calculate AS for each of the following reactions.(This problem requires values in your textbook's specific appendices, which you can access through the OWLV2 MindTap Reader. Youshould not use the OWLV2 References' Tables to answer this question as the values will not match.)1a. На (9) +H2O(1)AS isASJ/Kb. 2CH3 OH(9) + 302(g)2C02(9) + 4H20(g)AS isASJ/K%3DHBr(g) H (aq) + Br (ag)C.AS isAS =J/KSubmit AnswerTry Another Version1 item attempt remaining

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(This problem requires values in your textbook's specific appendices, which you can access through the OWLV2 MindTap Reader. Yo should not use the OWLV2 References' Tables to answer this question as the values will not match.) a. H; (9) +0 (9)-→ H;0(1) AS is AS = J/K b. 2CH3 OH(g) +302(g)→ 2CO2 (g) +4H2O AS is

(This problem requires values in your textbook's specific appendices, which you can access through the OWLV2 MindTap Reader. Yo should not use the OWLV2 References' Tables to answer this question as the values will not match.) a. H; (9) +0 (9)-→ H;0(1) AS is AS = J/K b. 2CH3 OH(g) +302(g)→ 2CO2 (g) +4H2O AS is

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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X OWLV2 | Online tea Car note CAU EMAIL CANVAS Pirate Ship MYJSCC BLACKBOARD Vacancies | A..| Birmingham New NCOER C (Review Topics] [References] Use the References to access important values if needed for this question. For the reaction 2 H20(1) 2 H2(g) + O2(g) AG° = 462.5 kJ and AH° 571.6 kJ at 334 K and 1 atm. This reaction is (reactant, product) favored under standard conditions at 334 K. The entropy change for the reaction of 2.05 moles of H2O(1) at this temperature would be J/K. Submit Answer Retry Entire Group 9 more group attempts remaining DEC 3 étv MacBook Air
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Review I Co Part A MISSED THIS? Read Section 19.6 (Papes 863 - 867): Watch KCV 19.6. IWE 19.4. AH =-98 kJ, AS-145 J/K, T = 297 K Calculate the change in Gibbs free energy for each of the following seots of AH, ASn, and T. (Assume that all reactants and products are in their standard states.) Express your answer as an integer. AG = kJ Submit Request Answer Part B AHan =-98 kJ, ASan =-145 J/K, T = 850 K Express your answer as an integer. AG kJ
O Microsoft OneDrive e teaching and lea x OWLV2 | Online teaching and lea X genow.com/ilrn/takeAssignment/takeCovalentActivity.do?locator=assignment-take Use the References to access important values if needed for this question. Consider the following system at equilibrium where AH° = -87.9 kJ/mol, and K. = 83.3 , at 500 K. PCI3 (g) + Cl2 (g) =PCI3 (g) When 0.30 moles of PCI5 (g) are added to the equilibrium system at constant temperature: The value of K. The value of Q. K. The reaction must Orun in the forward direction to restablish equilibrium. Orun in the reverse direction to restablish equilibrium. O remain the same. It is already at equilibrium. The concentration of Cl, will Submit Answer Retry Entire Group 9 more group attempts remaining Chp
Please help, I've been trying pretty hard and I'm on my last attempt. I understand the concept overAll but I'm still struggling. Thanks in advance.
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Mark the correct statements. (Select all that apply.) O [The reaction 2H20(g) → 2H2(g) + O2(g) is expected to have a positive value of ASº.] O [If a sample of pure ozone changed to oxygen at constant T and P, the entropy of the sample would decrease.] O [For the process H20(1) → H20(s) occurring at 0°C and 1 atm, the sign of AS is negative.] O [The value of AS for the process CHC13(1) – CHC13(g) is negative.] O [The reaction CH4(g) + 202(g) → CO2(g) + 2H2O(g) has a negative value of ASsurr-]
Using Appendix II from your textbook and DG°rxn for the reaction below, determine the standard Gibbs Free energy of formation, DG°F, for urea (CO(NH2)2) (aq). CO(NH2)2 (aq) + H20 (1) --> CO2 (g) + 2 NH3 (g) DG° = 13 kJ Edit View Insert Format Tools Table 12pt v Paragraph v BIUA 2v Tン: PrtScn
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2. · Both CCla (carbon tetrachloride) and CS2 (carbon disulfide) are liquids used as solvents in special industrial applications. Using data from the appendix and recognizing that S298 K(Cl02) = 257.22 J K-'mol-,calculate AH° and AG° for combustion of these liquids at 298 K: CCL,(1) + 502(g) 298K Co2(g) + 4C102(g) 298K CS2(1) + 302(g) - CO2(g) + 2so2(g) Based on your results, would you recommend special precautions against fires for industrial plants using either solvent? Explain your recommendations
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