Part C Using two very different method to solve for A,G, your answers from part A and part B will be the same. Why? O The reaction is spontaneous under all conditions Gibbs Energy is a state function Gibbs Energy is independent of temperature O The reaction is at equilibrium under standard conditions

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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DELET IEa
2 NO(g) + 02(9) → N,O.(g)
Use the following reactions with known A,G° values:
N204(9) + 2 NO: (g). A,G = 2.8 kJ mol
-1
NO(g) + 02(9) → NO2(9). A,G =- 36.3 kJ mol-
Express your answer using one decimal place.
A,G° = -75.4 kJ mol
Submit
Prevlous Answers
Completed
Part B
Now, calculate the A,G° for the same reaction, based on the Standard Gibbs Energies of formation:
AG"NO= 87.6 kJ - mol-
A,G"N,0,= 9.8 k.J - mol-1
A,G =
-75.4 kJ - mol-
Submit
Prevloue Anewere
Completed
Part C
Using two very different method to solve for A,G, your answers from part A and part B will be the same. Why?
O The reaction is spontaneous under all conditions
O Gibbs Energy is a state function
O Gibbs Energy is independent of temperature
O The reaction is at equilibrium under standard conditions
Transcribed Image Text:DELET IEa 2 NO(g) + 02(9) → N,O.(g) Use the following reactions with known A,G° values: N204(9) + 2 NO: (g). A,G = 2.8 kJ mol -1 NO(g) + 02(9) → NO2(9). A,G =- 36.3 kJ mol- Express your answer using one decimal place. A,G° = -75.4 kJ mol Submit Prevlous Answers Completed Part B Now, calculate the A,G° for the same reaction, based on the Standard Gibbs Energies of formation: AG"NO= 87.6 kJ - mol- A,G"N,0,= 9.8 k.J - mol-1 A,G = -75.4 kJ - mol- Submit Prevloue Anewere Completed Part C Using two very different method to solve for A,G, your answers from part A and part B will be the same. Why? O The reaction is spontaneous under all conditions O Gibbs Energy is a state function O Gibbs Energy is independent of temperature O The reaction is at equilibrium under standard conditions
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