DELET IEa2 NO(g) + 02(9) → N,O.(g)Use the following reactions with known A,G° values:N204(9) + 2 NO: (g). A,G = 2.8 kJ mol-1NO(g) + 02(9) → NO2(9). A,G =- 36.3 kJ mol-Express your answer using one decimal place.A,G° = -75.4 kJ molSubmitPrevlous AnswersCompletedPart BNow, calculate the A,G° for the same reaction, based on the Standard Gibbs Energies of formation:AG"NO= 87.6 kJ - mol-A,G"N,0,= 9.8 k.J - mol-1A,G =-75.4 kJ - mol-SubmitPrevloue AnewereCompletedPart CUsing two very different method to solve for A,G, your answers from part A and part B will be the same. Why?O The reaction is spontaneous under all conditionsO Gibbs Energy is a state functionO Gibbs Energy is independent of temperatureO The reaction is at equilibrium under standard conditions

Δr G0 is the enthalpy change for a reaction in the standard state. . It is given from the standard…

Part C Using two very different method to solve for A,G, your answers from part A and part B will be the same. Why? O The reaction is spontaneous under all conditions Gibbs Energy is a state function Gibbs Energy is independent of temperature O The reaction is at equilibrium under standard conditions

Part C Using two very different method to solve for A,G, your answers from part A and part B will be the same. Why? O The reaction is spontaneous under all conditions Gibbs Energy is a state function Gibbs Energy is independent of temperature O The reaction is at equilibrium under standard conditions

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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