This problem demonstrates a possible (though rare) situation that can occur with group comparisons. The groups are sections and the numerical variable being compared is an exam score.Section 1Section 2Section 376.25273.478.27171.788.865.282.586.866.175.475.188.183.170.191.779.983.173.478.692.549.486.68476.289.1 Perform a one-way ANOVA with α=0.05. Report the F test statistic rounded to 3 decimal places and the P-value rounded to 4 decimal places.F= p= What is the conclusion from the ANOVA?reject the null hypothesis: at least one of the group means is differentfail to reject the null hypothesis: not enough evidence to suggest the group means are differentCalculate the group means for each section (Rounded to 2 decimal places):Section 1: x¯1= Section 2: x¯2= Section 3: x¯3=

Name: This problem demonstrates a possible (though rare) situation that can
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: This problem demonstrates a possible (though rare) situation that can occur with group comparisons. The groups are sections and the numerical variable being compared is an exam score.Section 1Section 2Section 376.25273.478.27171.788.865.282.586.866.1

Answered: This problem demonstrates a possible…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Topic Video

Question

100%

This problem demonstrates a possible (though rare) situation that can occur with group comparisons. The groups are sections and the numerical variable being compared is an exam score.

Section 1	Section 2	Section 3
76.2	52	73.4
78.2	71	71.7
88.8	65.2	82.5
86.8	66.1	75.4
75.1	88.1	83.1
70.1	91.7	79.9
83.1	73.4	78.6
92.5	49.4	86.6
84	76.2	89.1

Perform a one-way ANOVA with α=0.05. Report the F test statistic rounded to 3 decimal places and the P-value rounded to 4 decimal places.
F=
p=
What is the conclusion from the ANOVA?
- reject the null hypothesis: at least one of the group means is different
- fail to reject the null hypothesis: not enough evidence to suggest the group means are different
Calculate the group means for each section (Rounded to 2 decimal places):
Section 1: x¯1=
Section 2: x¯2=
Section 3: x¯3=

Expert Solution

Step by step

Solved in 4 steps with 3 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Hypothesis Tests and Confidence Intervals for Means$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.

Similar questions