Answered: This is the TLC of syn-azobenzene (A…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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This is the TLC of syn-azobenzene (A for both plates since it was under UV light) and anti-azobenzene (B for both plates since it was not under UV light). Keep in mind that the original compound was azobenzene in toluene but we were trying to separate syn and anti-azobenzene. I included Rf values of each and I keep reading that the more polar compound should move slower and have a lower Rf but that is not the case here. The solvent used for the first one was 15% methylene chloride in pet. ether and for the second one, it was 30% methylene chloride in pet. ether. My quesiton is why did the syn-azobenzene travel further and why is its Rf higher? Does it have to do with the solvent in which I used 1.5 mL of methylene chloride and 8.5 mL pet. ether for the first plate and 3 mL methylene chloride for the second one with 7 mL of pet. ether?

J
15% 58mm
27.5mm
25.5%
A B
3
Rf
RF (A) 36%
30% 50MM
14 mm
50mm
14mm
= 27.5mm
Rf (A) 152 = 58mm = 0.47
Rf (B)₁55
8 mm
Rf (B) 30%. = 50mm
A
8MM
25.5mm = 0.44
58mm
B
6. 28
= 0.16
lib
ķ
a

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