This is a memoized version which uses a global array Q to store the results of computations. Memoization is useful to improve the running time from exponential to polynomial in dynamic programming. Algorithm below // Q is a large array of integers // initialized to -1 for (i=0; i< length[Q]; i++){ Q[i] = -1; } int Q-Optimal(int n) { print (Calling Q-Optimal with argument n); if (n = 0 or n=1) { Q[n] = n; return 1; } if (Q[n] != -1 ) { return Q[n]; } return (Q[n] = max (Q-Optimal(n-1), 1+Q-Optimal(n-2) ) ); } Question: If P(n) is the number of lines printed by Q-Optimal(n), write an explicit formula for P(n). Provide a detailed explanation why your formula is true.
This is a memoized version which uses a global array Q to store the results of computations. Memoization is useful to improve the running time from exponential to polynomial in dynamic programming. Algorithm below // Q is a large array of integers // initialized to -1 for (i=0; i< length[Q]; i++){ Q[i] = -1; } int Q-Optimal(int n) { print (Calling Q-Optimal with argument n); if (n = 0 or n=1) { Q[n] = n; return 1; } if (Q[n] != -1 ) { return Q[n]; } return (Q[n] = max (Q-Optimal(n-1), 1+Q-Optimal(n-2) ) ); } Question: If P(n) is the number of lines printed by Q-Optimal(n), write an explicit formula for P(n). Provide a detailed explanation why your formula is true.
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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This is a memoized version which uses a global array Q to store the results of computations. Memoization is useful to improve the running time from exponential to polynomial in dynamic programming.
// Q is a large array of integers
// initialized to -1
for (i=0; i< length[Q]; i++){
Q[i] = -1;
}
int Q-Optimal(int n) {
print (Calling Q-Optimal with argument n);
if (n = 0 or n=1) {
Q[n] = n;
return 1;
}
if (Q[n] != -1 ) {
return Q[n];
}
return (Q[n] = max (Q-Optimal(n-1), 1+Q-Optimal(n-2) ) );
}
Question: If P(n) is the number of lines printed by Q-Optimal(n), write an explicit formula for P(n). Provide a detailed explanation why your formula is true.
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