Given an unsorted array of integers, write a function in Python to find the length of the longest increasing subsequence (LIS) in the array. For example, given the array [10, 9, 2, 5, 3, 7, 101, 18], the LIS is [2, 3, 7, 101], which has a length of 4. Your solution should have a time complexity of O(n log n), where n is the length of the input array. Here's some code to get you started: def longest increasing_subsequence(arr): # TODO: implement function pass # example usage arr [10, 9, 2, 5, 3, 7, 101, 18] print(longest_increasing_subsequence(arr)) # should print 4
Given an unsorted array of integers, write a function in Python to find the length of the longest increasing subsequence (LIS) in the array. For example, given the array [10, 9, 2, 5, 3, 7, 101, 18], the LIS is [2, 3, 7, 101], which has a length of 4. Your solution should have a time complexity of O(n log n), where n is the length of the input array. Here's some code to get you started: def longest increasing_subsequence(arr): # TODO: implement function pass # example usage arr [10, 9, 2, 5, 3, 7, 101, 18] print(longest_increasing_subsequence(arr)) # should print 4
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![Given an unsorted array of integers, write a function in Python to find the length of the longest increasing subsequence (LIS) in the array. For example, given the array [10, 9, 2, 5, 3,
7, 101, 18], the LIS is [2, 3, 7, 101], which has a length of 4.
Your solution should have a time complexity of O(n log n), where n is the length of the input array.
Here's some code to get you started:
def longest increasing_subsequence(arr):
# TODO: implement function
pass
# example usage
arr = [10, 9, 2, 5, 3, 7, 101, 18]
print(longest_increasing_subsequence(arr)) # should print 4](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fee32db78-d067-4e55-9ba6-43f7e39e4b43%2Fec245b9e-c10b-4e47-ba1b-aa3853b9cbca%2Fxza3qds_processed.png&w=3840&q=75)
Transcribed Image Text:Given an unsorted array of integers, write a function in Python to find the length of the longest increasing subsequence (LIS) in the array. For example, given the array [10, 9, 2, 5, 3,
7, 101, 18], the LIS is [2, 3, 7, 101], which has a length of 4.
Your solution should have a time complexity of O(n log n), where n is the length of the input array.
Here's some code to get you started:
def longest increasing_subsequence(arr):
# TODO: implement function
pass
# example usage
arr = [10, 9, 2, 5, 3, 7, 101, 18]
print(longest_increasing_subsequence(arr)) # should print 4
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