This code segment find the value of the result of following series for five terms. * Y = X2 22 3X6 5X10 + 62 10² X = Val (Text1.Text) N=1: K=1: S=0: C=1 1-... ***** S=S+K*T K=-K: C=C+1 2- 3-.... GoTo 20 10 Text2.Text = Str(S) 1-20 T = (x^(2*N)) / ((2 *N)^2) 2-N = N +23-1f C = 6 Then Go To 10 1-20 T = (2*N) * (X^(2*N))/((2 *N) O^2) 2-N = N +23-lf C = 6 Then GoTo 10 1-20 T = (N) *(X^(2*N)) / ((2 *N)^ 2) 2-N = N +33-1fC = 6 Then GoTo 10 1-20 T = (N) *(X^(2*N)) / ((2 *N)^ 2) 2-N = N +23-If C = 5 Then GoTo 10 1-20 T = (N)*(X^(2*N)) / ((2 *N) ^ 2) 2-N=N+23-lf C = 4 Then GoTo 10 1-20 T = (N)*(X^(2*N))/((2 *N)^ 2) 2-N = N +23-lf C = 6 Then GoTo 20 1-20 T = (N)*(X^(2*N)) / ((2 *N) ^ 2) 2-N=N+2 3-lf C = 6 Then GoTo 10

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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This code segment find the
value of the result of following
series for five terms. *
Y
X = Val (Text1.Text)
N=1: K=1: S=0: C=1
1-.
X2 3X6 5X10
22 62 10²
+
S=S+K*T
K=-K: C=C+1
O
*****.
2-
3-.....
GoTo 20
10 Text2.Text = Str(S)
O
1-20 T = (x^(2*N))/ ((2 *N)^2) 2-N
= N +23-1f C = 6 Then Go To 10
1-20 T = (2*N) * (X^(2*N)) / ((2 * N)
^2) 2-N = N + 23-lf C = 6 Then GoTo
10
1-20 T = (N) * (X^(2* N)) / ((2 * N) ^
2) 2-N = N + 33-lf C = 6 Then GoTo 10
1-20 T = (N) * (X^(2 *N)) / ((2 * N) ^
2) 2-N = N + 23-1f C = 5 Then GoTo 10
1-20 T = (N) *(X^(2*N)) / ((2 *N) ^
2) 2-N = N +23-lf C = 41
= 4 Then GoTo 10
1-20 T = (N) * (X^(2 * N)) / ((2 * N) ^
2) 2-N = N +23-lf C = 6 Then GoTo 20
1-20 T = (N) * (X^ (2 * N)) / ((2 * N) ^
2) 2-N = N +23-1f C = 67
= 6 Then GoTo 10
Transcribed Image Text:This code segment find the value of the result of following series for five terms. * Y X = Val (Text1.Text) N=1: K=1: S=0: C=1 1-. X2 3X6 5X10 22 62 10² + S=S+K*T K=-K: C=C+1 O *****. 2- 3-..... GoTo 20 10 Text2.Text = Str(S) O 1-20 T = (x^(2*N))/ ((2 *N)^2) 2-N = N +23-1f C = 6 Then Go To 10 1-20 T = (2*N) * (X^(2*N)) / ((2 * N) ^2) 2-N = N + 23-lf C = 6 Then GoTo 10 1-20 T = (N) * (X^(2* N)) / ((2 * N) ^ 2) 2-N = N + 33-lf C = 6 Then GoTo 10 1-20 T = (N) * (X^(2 *N)) / ((2 * N) ^ 2) 2-N = N + 23-1f C = 5 Then GoTo 10 1-20 T = (N) *(X^(2*N)) / ((2 *N) ^ 2) 2-N = N +23-lf C = 41 = 4 Then GoTo 10 1-20 T = (N) * (X^(2 * N)) / ((2 * N) ^ 2) 2-N = N +23-lf C = 6 Then GoTo 20 1-20 T = (N) * (X^ (2 * N)) / ((2 * N) ^ 2) 2-N = N +23-1f C = 67 = 6 Then GoTo 10
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