Answered: onsider the following code and complete…

onsider the following code and complete the tracing table given below the code. sum = 0 for i in range (2,5): sum = sum + i * 2 for i in range (1,4): sum = sum + i

C++ for Engineers and Scientists

4th Edition

ISBN:9781133187844

Author:Bronson, Gary J.

Publisher:Bronson, Gary J.

Chapter4: Selection Structures

Section: Chapter Questions

Problem 14PP

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Q5. Below is the code for power function that computes x". Write the recurrence relation for this function. Solve the recurrence relation using master method (for dividing functions) long power(int x, int n) { if(n==0) return 1; if(x=0) return 0; if(n 1) return x; if(n%2 = 0) // n is even else } return power(x*x, n/2); return x * power(x*x, n/2);
Explain what the problem is in the table above! Including typeWhat is the problem? Make a solution with 2PL. How much the sum is please make the new table of 2pl
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A three stage amplifier is to have an overall noise temperature no greater than 7O K. The overall gain of the amplifier is to be at least 45 dB. The amplifier is to be built by adding a low-noise first stage to an existing two-stage amplifier that has the gains and noise figures shown below. The stage number refer to locations in the new amplifier. Stage Power Gain Noise Figure 20 dB 3 dB 13 15 dB 6 dB a. What is the minimum gain in decibels that the first stage can have? b. Using the gain you calculated in part (a), calculate the maximum noise figure in decibels that the first stage can have. Express answer with two decimal places. c. Suppose the gain of the first stage could be increased by 3 dB without affecting its noise figure. What would be the effect on the noise temperature of the complete amplifier?
Explain what the problem is in the table above! Including typeWhat is the problem? Make a solution with 2PL. How much the sum is
Assignment Write a program that calculates the revenue of a trip of a train composed of several train-cars. For the train, the user will give the total allowed train- car count (int), total allowed weight (double), and base speed (double). Then, the user will give train-car information for ALL train-cars that will TRY TO BE ADDED to the train. First, the number of train-cars will be given (int). For each train-car, three information will be given: type of the cargo (std:string), weight of the train-car (double), and how full the train-car is (int). After getting all this information, the program will TRY TO ADD each train-car to the train according to the train-car count and total allowed weight values. You CANNOT ADD a train-car to a train if it exceeds its train-car count. You CANNOT ADD a train-car to a train if by adding this train-car, the total weight of the train exceeds the train's total allowed weight. Each added train-car reduces the speed of the train by half its weight.…
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I want solution flowchart Start Step 1: Declare Student_Name[10], Student_Score[10][5],i=0,j=0,sum=0 Step 2: for i=0 to 9 Step 3: Get Student_Name[i] Step 4: for j=0 to 4 Step 5: Get Student_Score[i][j] Step 6: sum=sum+Student_Score[i][j] Step 7: End for Step 8: Print "Name= ",Student_Name[i] "Average=", (sum/5) Step 9: End for End
I want solution flowchart Start Step 1: Declare Student_Name[10], Student_Score[10][5],i=0,j=0,sum=0 Step 2: for i=0 to 9 Step 3: Get Student_Name[i] Step 4: for j=0 to 4 Step 5: Get Student_Score[i][j] Step 6: sum=sum+Student_Score[i][j] Step 7: End for Step 8: if (sum/5) > 90 and (sum/5)<=100 then Step 9: Print "Student Name= ", Student_Name[i] , "Grade= A+" Step 10: End if Step 11: else if (sum/5) > 80 and (sum/5)<=90 then Step 12: Print "Student Name= ", Student_Name[i] , "Grade= A" Step 13: End elseif Step 14: else if (sum/5) > 70 and (sum/5)<=80 then Step 15: Print "Student Name= ", Student_Name[i] , "Grade= B" Step 16: End elseif Step 17: else if (sum/5) > 60 and (sum/5)<=70 then Step 18: Print "Student Name= ", Student_Name[i] , "Grade= C" Step 19: End elseif Step 20: else Step 21: Print "Student Name= ", Student_Name[i] , "Grade= F" Step 22: End else Step 23: End for End
last 3 digits of enrolment number - 308 Let a, b and c denote the last three digits of your enrolment number (so for example with enrolment number 001054321, you would take a = 3, b = 2 and c = 1) and then take each of them (mod 2). So in the example above, a, b and c would become 1, 0, 1 respectively (each digit taken (mod 2)). Consider the polynomial . (a) Create a polynomial code of codeword length 8 from this generating polynomial. (b) Is your code cyclic? Justify your answer.