This coal gas can be used as fuel: CO(g)+H2(g) +O2(g) → CO,(g)+H2O(g) Predict the change in enthalpy for this combustion reaction from the following equations: 2 C(s) + O₂(g) → 2 CO(g) C(s) + O₂(g) → CO₂(g) 2 H₂(g) + O2(g) → 2 H₂O(g) ΔΗ = -222kJ AH-394kJ AH-484kJ Reaction 1 2 3 Reverse? Yes/No Multiply or Divide? If yes, by what?

This coal gas can be used as fuel: CO(g)+H2(g) +O2(g) → CO,(g)+H2O(g) Predict the change in enthalpy for this combustion reaction from the following equations: 2 C(s) + O₂(g) → 2 CO(g) C(s) + O₂(g) → CO₂(g) 2 H₂(g) + O2(g) → 2 H₂O(g) ΔΗ = -222kJ AH-394kJ AH-484kJ Reaction 1 2 3 Reverse? Yes/No Multiply or Divide? If yes, by what?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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2. จงหาค่า AH ของปฏิกิริยานี้ จากข้อมูลที่กำหนดให้ 2C (s) + 2 H,0 (g) → CH, (g) + CO,(g) Determine the standard enthalpy change for this reaction from the following standard enthalpies of reaction: (1) C(s) + H,O (g) → CÓ (g) + H, (g) AH° = 131.3kJ (2) CO (g) + H2O (g) → CO2 (g) + H2 (g) ΔΗΟ = -41.2 kJ (3) CH, (g) + H,O (g) → 3H, (g) + CO (g) AH° = 206.1kJ ชื่อ-สกุล .วันที่ เลขที่ เรหัส.. (0202104) จงหาค่า AH และ As ของปฏิกิริยานี้ จากข้อมูลที่กำหนดให้ 3 ปฏิกิริยาการสังเคราะห์ด้วยแสงเกิดขึ้นดังสมการ 6 CO, (g) + 6 H,0 (1) CH2O6 (S) + 6 0, (g) กำหนดค่าที่สภาวะมาตรฐานของ AH และ S ของสารแต่ละตัว ดังนี้ AH°, (kJ mol-') s° (JK-1 mol-') สาร | CH,206 (s) -1,273 212 O, (g) 205 2/2 CO, (g) -393 214 H,0 (1) -285 70
Given the two thermochemical equations below, find the enthalpy change for the reaction: N2H4 (l) + H2 (g) → 2 NH3 (g) delta H = ? Given: N2O4 (g) + 3 H2 (g) → 2 NH3 (g) + 2 O2 (g) delta H = – 100.96 kJ N2O4 (g) + 2 H2 (g) → N2H4 (l) + 2 O2 (g) delta H = + 41.47 kJ Select one: a. – 142.43 kJ b. – 59.49 kJ c. + 41.47 kJ d. + 59.49 kJ e. + 142.43 kJ f. none of these g. – 100.96 kJ
Determine the enthalpy of the reaction: 3Fe,O; (s) + CO (g) → CO, (g) + 2Fe;O4 (s), given the following reactions. 38. Fe,O3 (s) + 3CO (g) → 2Fe (s) + 3CO, (g) AH= -28.0 kJ 3Fe (s) + 4CO2 (s) → 4CO (g) + Fe;O4 (s) AH =+12.5 kJ A) 40.5 +109 -59.0 -109
For which one of the following is the enthalpy of the reaction the same as the enthalpy of formation? A) 2 H (g) + Se (s) → H:Se (g) B) KOH (s) → K*(aq) + OH- (aq) C) 2 Fe (s) + 3 Cl2 (g) → 2 FeCl3 (s) D) Ni (s) + ½ O2 (g)- NiO (s)
and 2 Enthalpy #1.30 enoindice pled TT 2010 2D49.bs 22) When 1 mole of Fe2O3(s) reacts with H₂(g) to form Fe(s) and H2O(g) according to the following equation, 98.8 kJ of energy are absorbed. (6 Fe2O3(s) + 3 H2(g) → 2 Fe(s) + 3 H₂O(g) (pp) (20/d4 (pm) $40 D Reaclanis 13:48 SH Products endothermic, A endothermic, B (2) exothermic, A exothermic, B nad W (21 Enthalpy MOMS. Reactants Products (A) (B) Is the reaction endothermic or exothermic, and which of the enthalpy diagrams above represents grow olor and to noin (01 this reaction? SH GH TH A HOMH X HILD 08.10 Page 6 of 8
The first step in the production of nitric acid from ammonia involves the oxidation of NH3. 4 NH3(g) + 5 O₂ (g) → 4 NO(g) + 6 H₂O(g) 2 a Use standard enthalpies of formation from the table below to calculate the standard enthalpy change for this reaction. Species AfH (kJ/mol) NH3(g) -45.90 NO(g) +90.29 H₂O(g) -241.83 Standard enthalpy change Submit = kJ/mol-rxn
From the following heats of combustion, Reaction Heat of Combustion CH, CH₂OH() + 30, (g) - 2C0₂(g) + 3H₂0 (1) C(s, diamond) + O₂(g) → CO₂(g) - H₂ (g) + O₂(g) → H₂0 (1) calculate the enthalpy of formation of ethanol (CH, CH₂OH) from its elements: 2C (s, diamond) + 3H₂(g) + O₂(g) → CH₂CH₂OH (1) -1366.8 -395.4 -285.81 mol
15. Use the following reactions for which the reaction enthalpies are given to determine the reaction enthalpy of: Given: N₂H40) + 2 H₂O2(1)→ N2(g) + 4H₂O N₂H4(1) + 3 O2(g) → 2 NO2(g) + 2 H₂O(g) H₂O(1) + 1/2O2(g) → H₂O2(1) 1/2 N2(g) + O2(g) → NO₂(g) H₂O → H₂O ΔΗ° = _466 kJ AH°= 98.0 kJ AH° = 34.0 kJ AH° = 44.0 kJ
See Periodic Table Table sugar (sucrose) is hydrolyzed to form glucose (a simple sugar) according to the following equation: CH,O1(s)+H,0(g) 2C,H,,0,(s) . Determine the enthalpy change for the hydrolysis reaction given the following information: C12H22011(s) + 120,(g) → 12CO, (g) + 11H,0(g) ΔΗ Ixn = -5640 kJ %3D CH1206(s) +60,(g) → 6CO,(g)+6H,0(g) ДН. Txn = -2800 kJ kJ
Using standard enthalpies of formation, determine the enthalpy of reaction for the following: a) CaO(s) + CO2(g) → CACO3(s) b) C2H2(g) + 2H2(g) → c) 4NH3(g) + 502(g) → 4NO(g) + 6H2O(g) C2H6(g)
Find the standard change in enthalpy for the following reaction. N₂H4(1) + O₂(g) → 2 NO(g) + 2 H₂O(g) Given the following known reactions: N₂(g) + 2 H₂(g) → N₂H₁ AH = 97.4 kJ/mol N₂(g) + O₂(g) → NO(g) AH = 90.2 kJ/mol H₂(g) + O₂(g) → H₂O(g) AH = -242 kJ/mol Remember you need to include O₂ to get a balanced reaction but its AH = 0 kJ/mol !!
The balanced thermochemical equation for the combustion of exactly one mole of propane is: C3H8 (g) + 5 O2 (g) → 3 CO2 (g) + 4 H2O(l) ΔH = -2220 kJ/mol What is the enthalpy change for the reaction: 1.5 CO2 (g) + 2 H2O(l) → 0.5 C3H8 (g) + 2.5 O2 (g) ΔH = ?