Thirty GPAs from a randomly selected sample of statistics students at a college are given in the accompanying table. Assume that the population distribution is approximately Normal. The technicianin charge of records claimed that the population mean GPA for the whole college is 2.86. A one-sided test with a significance level of 0.05 had previously been performed on the data and the nullhypothesis was rejected. Use the data to find a 95% confidence interval for the mean GPA. If a two-sided alternative had been used with a significance level of 0.05, would the hypothesized mean of2.86 have been rejected?Click the icon to view the data table.First, find the 95% confidence interval for the mean GPA.The confidence interval is ☐ to(Round to two decimal places as needed. Use ascending order.)Student GPA Table2.82 3.37 3.17 2.57 3.432.82 2.66 3.57 3.06 2.773.14 3.03 3.02 2.94 3.492.71 3.06 3.55 2.65 3.843.44 2.44 3.17 3.47 3.193.48 2.54 3.11 3.17 3.08exampleGet more helpPrintDonen- X√₁Vi(0,0)ΠMoreClear allFinal check

To work this problem out, we start by inputting those values into excel to figure out the mean and…

Answered: Thirty GPAs from a randomly selected…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A dietician wishes to see if a person’s cholesterol level will change if the diet is supplemented by a certain mineral. Six randomly selected subjects were pretested, and then they took the mineral supplement of a 6 week period. The results are shown in the table below. Can it be concluded that the cholesterol level has changed at a significance level of 0.10? Use the P-value method with your calculator. Assume the variable is approximately normally distributed. You can use your calculator to answer this question but make sure that you clearly write the statements for the null and alternative hypothesis. Be sure that you thoroughly explain your final conclusion using the P-value method. Subject 1 2 3 4 5 6 Before 210 235 208 190 172 244 After 190 170 210 188 173 228
If n=25 and the sample standard deviation is 15, construct a 95% confidence interval for the true standard deviation. (Assume the population is approximately Normal).
A random sample of high school students is used to estimate the mean time all high school students study for Algebra II tests. A 99% confidence interval based on this sample is: 1.7 hours to 3.1 hours. What is the sample mean?
ANSWER LETTER D,E,F only
Given two independent random samples with the following results: n₁ = 16 n₂ = 8 x₁ = 94 X2: $₁ = 16 = 124 $2 = 28 Use this data to find the 90% confidence interval for the true difference between the population means. Assume that the population variances are equal and that the two populations are normally distributed. Copy Data Step 2 of 3: Find the margin of error to be used in constructing the confidence interval. Round your answer to six decimal places.
A sociologist is comparing the proportion of teenage boys who receive a text message at least once an hour to the percentage of teenage girls who do. She has collected data from 150 men and 150 women. Which of the following is not a condition that the sociologist should check before creating a confidence interval for the difference in population proportions?
Suppose IQ scores were obtained for 20 randomly selected sets of couples. The 20 pairs of measurements yield x= 100.1, y = 98.3, r=0.961, P-value = 0.000, and y = - 18.02 + 1.16x, where x represents the IQ score of the wife. Find the best predicted value of y given that the wife has an IQ of 100? Use a significance level of 0.05. Click the icon to view the critical values of the Pearson correlation coefficient r. The best predicted value of y is (Round to two decimal places as needed.)
A survey of 32,782 adults in 2004 indicated that 24.6% of adults were current smokers. A similar study conducted in 1995 of 40,000 adults indicated that 29.7% were current smokers. a. Find and interpret a point estimate of the difference between the proportion of current smokers in 1995, and the proportion of current smokers in 2004. b. A 95% confidence interval for the true difference is (-0.058,-0.045). Interpret. c. What assumptions must you make for the confidence interval i part b to be valid? (…) a. Find a point estimate of the difference between the proportion of current smokers in 1995 and the proportion of current smokers in 2004. (Round to three decimal places as needed.)
create a 90% confidence interval for the following data: x = 25 n = 100
C. FIND t a n = 15 for the 98% confidence interval for the mean. %3D 2

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