A laboratory tested n = 101 chicken eggs and found that the mean amount of cholesterol was = 82 milligrams with o = 9 milligrams.Find the margin of error E corresponding to a 95% confidence interval for the true mean cholesterol content, u, of all such eggs.Round your answer to the nearest tenth.%3D%3D%3DType your answer...

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Answered: A laboratory tested n = 101 chicken…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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An arborist is interested in determining the mean diameter (in centimeters) of mature white oak trees at a certain height above the base. She measures 7 of these trees and finds the following sample statistics: F = 49.09 and s = interval for the mean diameter of a mature white oak tree. 13.80. Construct a 95% confidence
For a data set of the pulse rates for a sample of adult females, the lowest pulse rate is 39 beats per minute, the mean of the listed pulse rates is x = 78.0 beats per minute, and their standard deviation is s = 13.1 beats per minute. %3D a. What is the difference between the pulse rate of 39 beats per minute and the mean pulse rate of the females? b. How many standard deviations is that [the difference found in part (a)]? c. Convert the pulse rate of 39 beats per minutes to a z score. d. If we consider pulse rates that convert to z scores between - 2 and 2 to be neither significantly low nor significantly high, is the pulse rate of 39 beats per minute significant? a. The difference is beats per minute. (Type an integer or a decimal. Do not round.)
Suppose that for a test of proportion we have :p=0.5 and . The test statistic z=1.53 and the p-value is reported as P-value = 0.063. Find the error in the reasoning. This is a right-tailed test so the P-value should be 0.9370. This is a two-tailed test so the P-value should be 0.126. The P-value should have been calculated using the studentâ s t-distribution. There is no error in the reasoning. None of these.
Mensa is a society for "geniuses." One way to qualify for membership is having an IQ at least 2.5 standard deviations above average. IQs are approximately Normally distributed, according to the WAIS scale. The area to the left of a qualifying Mensa score is 0.9938, what percent of people should qualify? Note: If you use the table to look up the answer, that will give a decimal number. You must then multiply by 100 to convert the decimal to a percent. After multiplying by one hundred, round your answer to two decimal places. Your answer: Need help on this question? Getahint dewer point Show answT napoints)
Use z scores to compare the given values. The tallest living man at one time had a height of 225 cm. The shortest living man at that time had a height of 104.3 cm. Heights of men at that time had a mean of 173.55 cm and a standard deviation of 5.15 cm. Which of these two men had the height that was more extreme? Since the z score for the tallest man is z= and the z score for the shortest man is z= the V man had the height that was more extreme. (Round to two decimal places.)
The mean height of Americans in 1776 was 67 inches with a standard deviation of 3 inches. George Washington is believed to have been 6 ft 2 inches tall, or 74 inches. Between what two heights (in inches) do 68% of the heights fall? a.61 to 70 b.61 to 73 c.64 to 70
For a special pre–New Year’s Eve show, a radio station personality has invited a small panel of prominent local citizens to help demonstrate to listeners the adverse effect of alcohol on reaction time. The reaction times (in seconds) before and after consuming four drinks are in data below. At the 0.005 level, has the program host made his point? Identify and interpret the p-value for the test. Data: Subject Before After 1 0.32 0.39 2 0.39 0.44 3 0.36 0.49 4 0.41 0.53 5 0.37 0.46 6 0.42 0.52 7 0.41 0.52 8 0.43 0.46 9 0.39 0.55 10 0.41 0.52 11 0.35 0.45 12 0.42 0.41 13 0.32 0.54 14 0.39 0.46 15 0.41 0.53 16 0.33 0.54 17 0.43 0.46 18 0.42 0.43 19 0.41 0.52 20 0.35 0.52 21 0.39 0.41 22 0.39 0.44 23 0.32 0.50 24 0.33 0.53 25 0.31 0.45 26 0.35 0.45 27 0.31 0.45 28 0.32 0.48 29 0.38 0.54 30 0.37 0.46 31 0.39 0.49 32 0.30 0.51 33 0.40 0.49 34 0.41 0.50 35 0.41 0.53 36 0.35 0.47 37 0.37 0.51 38 0.41 0.46
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Find the area, square unit, to the nearest thousandth of the standard deviation between the given z-scores. Z equals 1.12 and z equals 1.73.
A successful basketball player has a height of 6 feet 11 inches, or 211 cm. Based on statistics from a data set, his height converts to the z score of 5.17. How many standard deviations is his height above the mean?
Isabella was told that her score on an aptitude test was 3 standard deviations above the mean. If test scores were approximately normal with μ=77 and σ=6, what was Isabella's score? Do not include units in your answer. For example, if you found that the score was 77 points, you would enter 77. Provide your answer below:
A data set lists weights (Ib) of plastic discarded by households. The highest weight is 5.72 Ib, the mean of all of the weights is x= 2.345 lb, and the standard deviation of the weights is s =2.123 lb. a. What is the difference between the weight of 5.72 lb and the mean of the weights? b. How many standard deviations is that (the difference found in part (a))? c. Convert the weight of 5.72 Ib to a z score d. If we consider weights that convert to z scores between -2 and 2 to be neither significantly low nor significantly high, is the weight of 5.72 Ib significant? a. The difference is lb. (Type an integer or a decimal. Do not round.) b. The difference is standard deviations. (Round to two decimal places as needed.) c. The z score is z= (Round to two decimal places as needed.) d. The highest weight is

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