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THERMODYNAMICS: Calculate the value of AH (in kJ) for the reaction, 2AR3 (g) + Q (s) → A2R4 (g) + QR2 (s) given the following hypothetical thermochemical equations: 2AR3 (g) + 2AX (g) → A2R4 (g) + 2XAR (g) AX (g) + ½R2 (g) → XAR (g) AH = -89.2 kJ AH = -158 kJ Q (s) + R2 (g) → QR2 (s) AH = -512.1 kJ %3D (Round off the final answer to ONE decimal place. Do not include the unit.)

THERMODYNAMICS: Calculate the value of AH (in kJ) for the reaction, 2AR3 (g) + Q (s) → A2R4 (g) + QR2 (s) given the following hypothetical thermochemical equations: 2AR3 (g) + 2AX (g) → A2R4 (g) + 2XAR (g) AX (g) + ½R2 (g) → XAR (g) AH = -89.2 kJ AH = -158 kJ Q (s) + R2 (g) → QR2 (s) AH = -512.1 kJ %3D (Round off the final answer to ONE decimal place. Do not include the unit.)

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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QUESTION 11 THERMODYNAMICS: Calculate the value of AH (in kJ) for the reaction, 2AR3 (g) + Q (s)→A2R4 (g) + QR2 (s) given the following hypothetical thermochemical equations: 2AR3 (g) + 2AX (g) →A2R4 (g) + 2XAR (g) AH = -89.2 kJ AX (g) + ½R2 (g) → XAR (g) AH = -158 kJ -> Q (s) + R2 (g) → QR2 (s) AH = -512.1 kJ %3D (Round off the final answer to ONE decimal place. Do not include the unit.)
Transcribed Image Text:QUESTION 11 THERMODYNAMICS: Calculate the value of AH (in kJ) for the reaction, 2AR3 (g) + Q (s)→A2R4 (g) + QR2 (s) given the following hypothetical thermochemical equations: 2AR3 (g) + 2AX (g) →A2R4 (g) + 2XAR (g) AH = -89.2 kJ AX (g) + ½R2 (g) → XAR (g) AH = -158 kJ -> Q (s) + R2 (g) → QR2 (s) AH = -512.1 kJ %3D (Round off the final answer to ONE decimal place. Do not include the unit.)
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