There is a popular lottery in which a ticket is called a scratcher. An advertisement for this lottery claims that 62% of the population of all the scratchers are winning ones. You want to research this daim by selecting a random sample of 25 scratchers. Follow the steps below to construct a 90% confidence interval for the population proportion of all winning scratchers. Then state whether the confidence interval you construct contradicts the advertisement's claim. (If necessary, consult a list of formulas.) (a) Click on "Take Sample" to see the results from the random sample. Number Proportion Take Sample Winning scratcher 11 0.44 Losing scratcher 14 0.56 Enter the values of the sample size, the point estimate of the population proportion, and the critical value you need for your 90% confidence interval. (Choose the correct critical value from the table of critical values provided.) When you are done, select "Compute". Sample size: Standard error: Critical values Point estimate: F0.00s -2.576 Margin of error: 20.010-2.326 Critical value: F0.025 -1.960 90% confidence interval: 20oso1.645

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There is a popular lottery in which a ticket is called a scratcher. An advertisement for this lottery claims that 62% of the population of all the scratchers are
winning ones. You want to research this daim by selecting a random sample of 25 scratchers.
Follow the steps below to construct a 90% confidence interval for the population proportion of all winning scratchers. Then state whether the confidence interval
you construct contradicts the advertisement's claim. (If necessary, consult a list of formulas.)
(a) Click on "Take Sample" to see the results from the random sample.
Number
Proportion
Take Sample
Winning scratcher
11
0.44
Losing scratcher
14
0.56
Enter the values of the sample size, the point estimate of the population proportion, and the critical value you need for your 90% confidence interval.
(Choose the correct critical value from the table of critical values provided.) When you are done, select "Compute".
Sample size:
Standard error:
Critical values
Point estimate:
20.005 -2.576
Margin of errors
20.010-2.326
Critical value:
F0.0251.960
90% confidence interval:
Z0.050 =1.645
Compute
Zn100-1.282
Explanation
Check
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Transcribed Image Text:There is a popular lottery in which a ticket is called a scratcher. An advertisement for this lottery claims that 62% of the population of all the scratchers are winning ones. You want to research this daim by selecting a random sample of 25 scratchers. Follow the steps below to construct a 90% confidence interval for the population proportion of all winning scratchers. Then state whether the confidence interval you construct contradicts the advertisement's claim. (If necessary, consult a list of formulas.) (a) Click on "Take Sample" to see the results from the random sample. Number Proportion Take Sample Winning scratcher 11 0.44 Losing scratcher 14 0.56 Enter the values of the sample size, the point estimate of the population proportion, and the critical value you need for your 90% confidence interval. (Choose the correct critical value from the table of critical values provided.) When you are done, select "Compute". Sample size: Standard error: Critical values Point estimate: 20.005 -2.576 Margin of errors 20.010-2.326 Critical value: F0.0251.960 90% confidence interval: Z0.050 =1.645 Compute Zn100-1.282 Explanation Check D 2021 McGraw-Hill Education. All Rights Reserved Terms of Use I Privacy I Accessi MacBook Air $ % & 2 3 4 5 6 8 Q W E T. Y A S F G K C V 92 command command
(b)
Based on your sample, graph the 90% confidence interval for the population proportion of all winning scratchers.
· Enter the values for the lower and upper limits on the graph to show your confidence interval.
• For the point (), enter the claim 0.62 from the advertisement.
90% confidence interval:
0.000
1.000
0.620
0.000
1.000
(c)
Does the 90% confidence interval you constructed contradict the claim from the advertisement?
Choose the best answer from the choices below.
O No, the confidence interval does not contradict the claim. The proportion 0.62 from the advertisement is inside the 90%
confidence interval.
O No, the confidence interval does not contradict the claim. The proportion 0.62 from the advertisement is outside the
90% confidence interval.
O Yes, the confidence interval contradicts the claim. The proportion 0.62 from the advertisement is inside the 90%
confidence interval.
O Yes, the confidence interval contradicts the claim. The proportion 0.62 from the advertisement is outside the 90%
confidence interval.
Explanation
Check
2021 McGraw-Hill Education. AlI Rights Reserved
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Transcribed Image Text:(b) Based on your sample, graph the 90% confidence interval for the population proportion of all winning scratchers. · Enter the values for the lower and upper limits on the graph to show your confidence interval. • For the point (), enter the claim 0.62 from the advertisement. 90% confidence interval: 0.000 1.000 0.620 0.000 1.000 (c) Does the 90% confidence interval you constructed contradict the claim from the advertisement? Choose the best answer from the choices below. O No, the confidence interval does not contradict the claim. The proportion 0.62 from the advertisement is inside the 90% confidence interval. O No, the confidence interval does not contradict the claim. The proportion 0.62 from the advertisement is outside the 90% confidence interval. O Yes, the confidence interval contradicts the claim. The proportion 0.62 from the advertisement is inside the 90% confidence interval. O Yes, the confidence interval contradicts the claim. The proportion 0.62 from the advertisement is outside the 90% confidence interval. Explanation Check 2021 McGraw-Hill Education. AlI Rights Reserved MacBook Air 吕口 F7 # 2$ & 2 4 5 8 Q W E T Y S D F K. しの つ くo
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