(b) Based on your sample, graph the 90% confidence interval for the population proportion of all winning scratchers.•Enter the values for the lower and upper limits on the graph to show your confidence interval.For the point (*), enter the claim 0.55 from the advertisement.0.0000.00090% confidence interval:0.500(c)Does the 90% confidence interval you constructed contradict the claim from the advertisement?Choose the best answer from the choices below.1.0001.000○ No, the confidence interval does not contradict the claim. The proportion 0.55 from the advertisement is inside the90% confidence interval.No, the confidence interval does not contradict the claim. The proportion 0.55 from the advertisement is outsidethe 90% confidence interval.Yes, the confidence interval contradicts the claim. The proportion 0.55 from the advertisement is inside the 90%confidence interval.○ Yes, the confidence interval contradicts the claim. The proportion 0.55 from the advertisement is outside the 90%confidence interval. There is a popular lottery in which a ticket is called a scratcher. An advertisement for this lottery claims that 55% of the population of all the scratchers arewinning ones. You want to research this claim by selecting a random sample of 35 scratchers.Follow the steps below to construct a 90% confidence interval for the population proportion of all winning scratchers. Then state whether the confidence intervalyou construct contradicts the advertisement's claim. (If necessary, consult a list of formulas.)(a) Click on "Take Sample" to see the results from the random sample.NumberProportionTake SampleWinning scratcherLosing scratcher140.4210.6Enter the values of the sample size, the point estimate of the population proportion, and the critical value you need for your 90% confidenceinterval. (Choose the correct critical value from the table of critical values provided.) When you are done, select "Compute".Sample size:Point estimate:Critical value:ComputeStandard error:GCritical valuesMargin of error:-0.005 = 2.576-0.010 -2.326-0.025 -1.96090% confidence interval:-0.050 1.6450.100 1.282

The sample size is scrachers. The result from the sample size is shown below,…

Answered: There is a popular lottery in which a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A newspaper article stated that the US Supreme Court received 812 letters from around the country on the subject of whether to ban cameras from the courtroom. Of these 812 letters, 800 expressed the opinion that cameras should be banned. A statistics student was going to use this sample information to estimate a 95% confidence interval for the true proportion of all American adults feel that cameras should be banned from the courtroom. what is the 95% confidence interval?
Your statistics instructor claims that 60 percent of the students who take her Elementary Statistics class go through life feeling more enriched. For some reason that she can't quite figure out, most people don't believe her. You decide to check this out on your own. You randomly survey 64 of her past Elementary Statistics students and find that 34 feel more enriched as a result of her class. Construct a 95% confidence interval for the true mean or proportion. Round to the nearest hundredth (2 decimal places). ( , )
if n=20, x=43, and s=9, construct a confidence interval at a 98% confidence level, the data came from a normally distributed population.
Elvin wants to know how the school views him as their leader. He asked his friend, Marcus, to research it. After a week, Marcus told him that a sample of 400 schoolmates selected at random indicated that 58% of them hold him in high regard. Determine the confidence interval at 60% confidence level.
in a town in nj we take a random sample of 100 residents. It turns out that 25% of the adult residents have degrees higher than high school diploma. Find a 90% confidence interval.
If n = 440 and p = 0.52, construct a 90% confidence interval. %3D Give your answers to three decimals
According to some car loan statistics, 44% of Americans are relying on an auto loan to pay for their cars. Assuming this finding to be based on a simple random sample of 1500 Americans, construct and interpret the 95% confidence interval for the population proportion of Americans who have a car loan.
A research company is interested in determining the true proportion of Americans that work remotely. In a random sample of 200 individuals, 4.5% of them work remotely. Find a 90% confidence interval for the true proportion of Americans that work remotely.
I'm having trouble trying to figure out how to work the problem below out. Let’s say that 44 percent of the 1,300 U.S. adults who responded to a poll about marijuana legalization said they support legalization. Let’s also say the margin of error for the results is +/- 3 percentage points. The margin of error tells us there’s a high probability that nationwide support for marijuana legalization falls: The correct interpretation of this confidence interval is:
When Mendel conducted his famous genetics experiments with peas, one sample of offspring consisted of 428 green peas and 152 yellow peas. 3. a. Find a 99% confidence interval estimate of the percentage of yellow peas.
In the Star and Tribune newspaper, there is an article entitled "1 in 8 school buses fail tests." The article says that the overall statewide proportion of school buses that fail safety tests is 9%. However, one bus company has a higher rate of over 12%. Assume that we want a new estimate for the statewide proportion of school buses that fail the safety inspection. How large a sample would you have to take in order to construct a 95% confidence interval estimate for the true proportion of buses that fail the inspection and achieve a margin of error of plus or minus 2%? (your answer should be an integer)
If the confidence interval is (0.32, 0.48) and the sample size is 100. What is x?

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