Most people can roll their tongues, but many people can't. Whether or not a person can roll his tongue is genetically determined. Suppose we are interested in determining what percentage of students can roll their tongues. We get a simple random sample of 400 students and find that 317 can roll their tongues. The margin of error for a 95% confidence interval for the true percentage of tongue-rollers among students is closest to

Q: According to a poll, 81% of California adults (409 out of 506 surveyed) feel that education is one…

A: Point estimate=0.81

Q: A student would like to estimate the proportion of the senior class that plans to attend prom this…

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Q: A poll for a statewide election has a margin of error of 2.14 percentage points. How many voters…

A: From the provided information,Margin of error (E) = 0.0214Confidence level = 99%

Q: Public Policy Polling recently conducted a survey asking adults across the U.S. about music…

A: Given data  N = 571 X = 80 99% confidence interval

Q: Greece has faced a severe economic crisis since the end of 2009. A Gallup poll surveyed 1,000…

A:

Q: 1. A survey of 224 children of ages 9 to 17 was conducted shortly after 1986 space-shuttle disaster.…

A:

Q: Suppose we want to estimate the proportion of teenagers (aged 13-18) who are lactose intolerant. If…

A: Given information Error = 2% = 0.02 Confidence level = 0.95

Q: You are told that a survey produced a 90% confidence interval for the mean spent on utilities per…

A:

Q: a recent study of 100 people in Burlingame found that 19 were obese.  Find the 90% confidence…

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Q: The administration at a community college wants to estimate the number of parking spaces they will…

A: Given Information: Sample size (n) = 80 Out of which 75 students in the sample drive to campus by…

Q: 99% confidence interval for the proportion of the high school students who have been cyberbullied,…

A: Given that Sample size n = 14795 Number of high school students who have cyberbullied, X = 2219 The…

Q: You plan to conduct a survey to find out the proportion of students who enjoy taking classes…

A: Given  The margin of error is given as m=0.02 At a 90% confidence interval, α=0.1 As the proportion…

Q: confidence interval for the mean of five measurements is smaller than for a single result.

A: Here we use confidence interval formula for explanations as given in step 2

Q: Insurance companies are interested in knowing the population percent of drivers who always buckle up…

A: Given: n=394x=298 The sample proportion is. p^=xn=298394=0.7563 From the Standard Normal Table, the…

Q: A poll reported 60% support for a statewide election with a margin of error of 3.35  percentage…

A: The question is about sample size estimationGiven :Proportion of voters who supports for a statewide…

Q: A poll reported 37% support for a statewide election with a margin of error of 4.18 percentage…

A:

Q: Question 15 What effect does sample size have on the width of the confidence interval? Changing the…

A: In the general sense, sample size is inversely proportional to the width of the confidence interval.…

Q: A high school counselor is interested in determining factors that contribute to high school drop out…

A: Solution; Given information: n1=41 Sample size of high school  graduatesn2= 38 Sample size of high…

Q: In a random sample of 575 American goods, about 46.3% of them were transported by rail in 2017.…

A: Given,   Sample size = 575 Sample proportion = 0.463   Critical value: Using z-table, the z-critical…

Q: Sam computed a 90% confidence interval for mean from a specific random sample size n. He claims that…

A: Given Information: Sam computed a 90% confidence interval for mean from a specific random sample of…

Q: A marketing survey involves product recognition in New York and California. Of 558 New Yorkers…

A:

Q: In a survey conducted by CNN, 130 of the 250 people that were randomly surveyed have a savings…

A: Given data, n=250 x=130 Sample proportion p=x/n =130/250=0.52 z-value at 90% confidence is Zc=1.645

Q: The principal randomly selected six students to take an aptitude test. Their scores were 72.3 81.1…

A: Data given: 72.3, 81.1, 78.4, 80.9, 81.5, 75.5  Calculate mean: mean=72.3+81.1+78.4+80.9+81.5+75.5…

Q: A survey was conducted where 27 students were asked which social media app is their favorite,…

A: Given information: A survey consisted of n = 27 students. They were asked for their favorite social…

Q: n a town in nj we take a random sample of 100 residents. It turns out that 25% of the adult…

A: Given Data: p=0.25 n=100   z-value for 90% Confidence level=1.645

Q: Suppose a 90 percent confidence interval to estimate a population proportion was calculated from a…

A: The confidence interval for proportion can be calculated as follows:

Q: According to recent data by the American Marketing​ Association, 76.5​%of people in the​ 18-24 age…

A:

Q: 24. Job Interviews In a Harris poll of 514 human resource professionals, 90% appearance of a job…

A: Hello! As you have posted more than 3 sub parts, we are answering the first 3 sub-parts.  In case…

Q: Example : In the group of 345 children surveyed, the sample mean was 11.3 and the standard deviation…

A:

Q: a. Find 90% confident interval for the proportion of defective parts produced by a company. Keep two…

A: It is given asSample size, n = 50Favourable cases, x = 6