There is a part 3 but it won’t let me attach another picture. It wants to solve [SO3] at equilibrium. I’m have the first two parts but don’t know how to solve for SO3 equilibrium.

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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There is a part 3 but it won’t let me attach another picture. It wants to solve [SO3] at equilibrium. I’m have the first two parts but don’t know how to solve for SO3 equilibrium. The information for the problem is in the first two pictures that are needed
10:44
Kc =
At high temperature, SO₂ and O₂ react
according to the equation below. Determine
the concentration of SO₂ at equilibrium for this
reaction by constructing an ICE table, writing
the equilibrium constant expression, and
solving for the concentration of SO3 at
equilibrium. Complete Parts 1-3 before
submitting your answer.
2 SO₂(g) + O₂(g) = 2 SO3(g)
2
3
[x]
[0.0216 -x]
[0.0216 - 2x]
Question 12 of 28
1
[0.0148 -x]
[0.0148 - 2x]
The equilibrium constant for the formation of
SO3 has a Kc equal to 3.01 x 10³ at 900 K.
Using the data from your ICE Table construct
the expression for the equilibrium constant.
Each reaction participant must be represented
by one tile. Do not combine terms.
[x]²
[0.0216 + x]
[0.0216 + 2x]
[0.0148 + x]
[0.0148 + 2x]
[2x]
[0.0216 -x]²
98
[0.0216 - 2x]²
Submit
= 3.01 x 10³
[0.0148 -x]²
[0.0148 - 2x]²
Tap here or pull up for additional resources
RESET
[2x]²
[0.0216 + x]²
[0.0216 + 2x]²
[0.0148 + x)²
[0.0148 + 2x]²
Transcribed Image Text:10:44 Kc = At high temperature, SO₂ and O₂ react according to the equation below. Determine the concentration of SO₂ at equilibrium for this reaction by constructing an ICE table, writing the equilibrium constant expression, and solving for the concentration of SO3 at equilibrium. Complete Parts 1-3 before submitting your answer. 2 SO₂(g) + O₂(g) = 2 SO3(g) 2 3 [x] [0.0216 -x] [0.0216 - 2x] Question 12 of 28 1 [0.0148 -x] [0.0148 - 2x] The equilibrium constant for the formation of SO3 has a Kc equal to 3.01 x 10³ at 900 K. Using the data from your ICE Table construct the expression for the equilibrium constant. Each reaction participant must be represented by one tile. Do not combine terms. [x]² [0.0216 + x] [0.0216 + 2x] [0.0148 + x] [0.0148 + 2x] [2x] [0.0216 -x]² 98 [0.0216 - 2x]² Submit = 3.01 x 10³ [0.0148 -x]² [0.0148 - 2x]² Tap here or pull up for additional resources RESET [2x]² [0.0216 + x]² [0.0216 + 2x]² [0.0148 + x)² [0.0148 + 2x]²
10:43
Initial (M)
Change (M)
At high temperature, SO₂ and O₂ react
according to the equation below. Determine
the concentration of SO₂ at equilibrium for this
reaction by constructing an ICE table, writing
the equilibrium constant expression, and
solving for the concentration of SO3 at
equilibrium. Complete Parts 1-3 before
submitting your answer.
2 SO₂(g) + O₂(g) = 2 SO3(g)
1
2
3
An initial mixture of 0.0216 mol SO₂ and
0.0148 mol O₂ reacted in a 1.0 L vessel. Fill in
the ICE table with the appropriate value for
each involved species to determine the
unknown.
Equilibrium (M)
1.0
-2x
Question 12 of 28
0.0216 - 2x
0
2SO₂(g) + O₂(g) = 2SO3(g)
+
+x
0.0216 + x
0.0148 + x
0.0216
+2x
0.0216 + 2x
0.0148 + 2x
Submit
0.01.10
Tap here or pull up for additional resources
98
RESET
0.0148
-X
0.0216 - x
0.0148 - x
Transcribed Image Text:10:43 Initial (M) Change (M) At high temperature, SO₂ and O₂ react according to the equation below. Determine the concentration of SO₂ at equilibrium for this reaction by constructing an ICE table, writing the equilibrium constant expression, and solving for the concentration of SO3 at equilibrium. Complete Parts 1-3 before submitting your answer. 2 SO₂(g) + O₂(g) = 2 SO3(g) 1 2 3 An initial mixture of 0.0216 mol SO₂ and 0.0148 mol O₂ reacted in a 1.0 L vessel. Fill in the ICE table with the appropriate value for each involved species to determine the unknown. Equilibrium (M) 1.0 -2x Question 12 of 28 0.0216 - 2x 0 2SO₂(g) + O₂(g) = 2SO3(g) + +x 0.0216 + x 0.0148 + x 0.0216 +2x 0.0216 + 2x 0.0148 + 2x Submit 0.01.10 Tap here or pull up for additional resources 98 RESET 0.0148 -X 0.0216 - x 0.0148 - x
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