3. In a 2.0 L container an equilibrium exists between 0.400 mol of N202, 0.600 mol of H2, 1.000 mol of N20 and 1.000 mol of H₂O. N₂O2 (g) + H₂ (g) = N₂O(g) + H₂O(g) If 0.200 mol of N₂02 is added, what will the new equilibrium concentrations be of N₂O(g) + H₂O(g)?
3. In a 2.0 L container an equilibrium exists between 0.400 mol of N202, 0.600 mol of H2, 1.000 mol of N20 and 1.000 mol of H₂O. N₂O2 (g) + H₂ (g) = N₂O(g) + H₂O(g) If 0.200 mol of N₂02 is added, what will the new equilibrium concentrations be of N₂O(g) + H₂O(g)?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Answers are attached. Please show all steps and make an ICE table. Thank you!
![3 [H₂0] = [N₂0] = 0.537M](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbeaa6890-e5db-44c8-b5cd-a4b86da11d95%2Ff7bcfbab-c21e-4ee3-9031-9fd56b690cc6%2Fdqeott8_processed.png&w=3840&q=75)
Transcribed Image Text:3 [H₂0] = [N₂0] = 0.537M
Transcribed Image Text:3.
In a 2.0 L container an equilibrium exists between 0.400 mol of N202, 0.600 mol of H₂, 1.000 mol of
N₂0 and 1.000 mol of H₂O.
N₂O2 (g) + H₂ (g) = N₂O(g) + H₂O(g)
If 0.200 mol of N₂02 is added, what will the new equilibrium concentrations be of N2O(g) + H₂O(g)?
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