I am having trouble with these incorrect solution There are two traffic lights on a commuter's route to and from work. Let X, be the number of lights at which the commuter must stop on his way to work, and X, be the number of lights at which he must stop when returning from work. Suppose that these two variables areindependent, each with the pmf given in the accompanying table (so X,, X, is a random sample of size n = 2).12X1p(x1) 0.3 0.4 0.3u = 1, o? = 0.6(a) Determine the pmf ofX1 + X2.2341to0.340.240.090.24p(t,) ||0.09(b) Calculate= 2PT.How does it relate to u, the population mean?= 2PT.2(c) CalculateOTTo2%3D2OTOHow does it relate to o, the population variance?2OTO= the sum of all four X,'s, what now are the values of E(T) and V(T)?(d) Let X, and X, be the number of lights at which a stop is required when driving to and from work on a second day assumed independent of the first day. With T.E(T,)4V(T,)2.4(e) Referring back to (d), what are the values of P(T, = 8) and P(T, 2 7) [Hint: Don't even think of listing all possible outcomes!]0.0081P(T, = 8)0.0405P(T, > 7)

Note: Hi! Thank you for the question. As you have specified, we have helped you answer only the…

There are two traffic lights on a commuter's route to and from work. Let X, be the number of lights at which the commuter must stop on his way to work, and X, be the number of lights at which he must stop when returning from work. Suppose that these two variables are Independent, each with the pmf given in the accompanying table (so X,, X, is a random sample of size n= 2). P(x,) 0.3 0.4 0.3 - 1, o? - 0.6 (a) Determine the pmf of T,- X, + X. to 1 2 p(t,) 0.09V 0.24 0.34 V 0.24 V 0.09 (b) Calculate T HT, - 2 How does relate to , the population mean? HT.2 (c) Calculate a. - 2 How does relate to o, the population variance? 2- (d) Let X3 and X4 be the number of lights at which a stop is required when driving to and from work on a second day assumed independent of the first day. With T, - the sum of all four X's, what now are the values of E(T) and V(T)? E(T) - 4 V(T) - 24 (e) Referring back to (d), what are the values of P(T, - 8) and P(T, 2 7) (Hint: Don't even think of listing all possible outcomes!] P(T, - 8) - 0.0081 P(T, 2 7) - 0.0405

There are two traffic lights on a commuter's route to and from work. Let X, be the number of lights at which the commuter must stop on his way to work, and X, be the number of lights at which he must stop when returning from work. Suppose that these two variables are Independent, each with the pmf given in the accompanying table (so X,, X, is a random sample of size n= 2). P(x,) 0.3 0.4 0.3 - 1, o? - 0.6 (a) Determine the pmf of T,- X, + X. to 1 2 p(t,) 0.09V 0.24 0.34 V 0.24 V 0.09 (b) Calculate T HT, - 2 How does relate to , the population mean? HT.2 (c) Calculate a. - 2 How does relate to o, the population variance? 2- (d) Let X3 and X4 be the number of lights at which a stop is required when driving to and from work on a second day assumed independent of the first day. With T, - the sum of all four X's, what now are the values of E(T) and V(T)? E(T) - 4 V(T) - 24 (e) Referring back to (d), what are the values of P(T, - 8) and P(T, 2 7) (Hint: Don't even think of listing all possible outcomes!] P(T, - 8) - 0.0081 P(T, 2 7) - 0.0405

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Similar questions

15. Which of the following equations does NOT have an extraneous solution? A. x-2= 2-x B. x+1=Vx² -5 C. V2x+15 = x D. Vx-1 = x-7
Our book page 23 #5. Solve for x₁,x₂and x3 x₁ + x₂ + 2x₂ = 8 -x₁ −2x₂ + 3x₂ = 1 = 10 3x₁ - 7x₂ + 4x3 =
Hello, Can you explain problem c) I do not understand the solution.
I am having trouble understanding the solution. Also the hints do not seem to be used. Some elaboration would be great, thanks!
Find the particular solution of (2x + 3)y = y + (2x + 3)/2; when x = -1, y = 0 Show your solutions on a separate sheet of paper. A 2x = (-2x + 3)1/2 (2y + 3) B 2y = (2x + 3)1/2 (2x + 3) © 2x = (2y + 3)1/2 (2x - 3) D 2y = (2x - 3)1/2 (2x + 3)
Solve the problem below. For your initial post in Brightspace, copy the description of your company given in the box below and then enter your solution to all three parts (parts a, b, and c) of the problem. To copy the description of your company, highlighting and using "copy" from here in Mobius and then using "paste" into Brightspace should work. However, if when you copy and paste x you get a 2 instead, then change your x2 to x^2. Hint: We covered this topic in "2-1 Reading and Participation Activities: Quadratic Equations" in Module Two. You can check your answer to part b to make sure that you are on the right track. For a certain company, the cost for producing x items is 40x +300 and the revenue for selling a items is 80r - 0.5x2. The profit that the company makes is how much it takes in (revenue) minus how much it spends (cost). In economic models, one typically assumes that a company wants to maximize its profit, or at least wants to make a profit! Part a: Set up an expression…
Please, expert, I want a solution to all the paragraphs. This is one question, but it has multiple paragraphs.
Hello, I have been stuck on this question for a while now. I believe I did all the steps right thus far if I did not make a mistake somewhere down the line, I have not been able to find a way to know what A=? and what B=? could anyone spot a mistake that I could have made down the line or what might be my next step to finally finding what A and B are equal to? Thanks, you!
How can I solve these two subtituions problem? 1- y= 3x-3 4x-2y=-2 2) 4x+3y--1 6x-5y=27