x-9 +²+3x-10 }} A Y + B X-2 x-q (*+5)(x-2) X-9 = A (x-2) + B (x+5) AX-2 A+B x + S B (A + B) x + (S1B3 - 216) IB A = B =

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter8: Polynomials
Section8.3: Multiplying Polynomials
Problem 54PFA
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Hello, I have been stuck on this question for a while now. I believe I did all the steps right thus far if I did not make a mistake somewhere down the line, I have not been able to find a way to know what A=? and what B=? could anyone spot a mistake that I could have made down the line or what might be my next step to finally finding what A and B are equal to? 

Thanks, you!

X-9
+² +3x-10
A
x+s
||
+ B
X-2
x-9
(x+5)(x-2)
X-9 = A (x-2) + B(x+5)
AX-2A + B x + 5 B
(A + B) x + (SB3 - 2 16)
R =
B =
Transcribed Image Text:X-9 +² +3x-10 A x+s || + B X-2 x-9 (x+5)(x-2) X-9 = A (x-2) + B(x+5) AX-2A + B x + 5 B (A + B) x + (SB3 - 2 16) R = B =
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