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x-9 +²+3x-10 }} A Y + B X-2 x-q (*+5)(x-2) X-9 = A (x-2) + B (x+5) AX-2 A+B x + S B (A + B) x + (S1B3 - 216) IB A = B =

x-9 +²+3x-10 }} A Y + B X-2 x-q (*+5)(x-2) X-9 = A (x-2) + B (x+5) AX-2 A+B x + S B (A + B) x + (S1B3 - 216) IB A = B =

Elementary Algebra
Elementary Algebra
17th Edition
ISBN:9780998625713
Author:Lynn Marecek, MaryAnne Anthony-Smith
Publisher:Lynn Marecek, MaryAnne Anthony-Smith
Chapter6: Polynomials
Section6.7: Integer Exponents And Scientific Notation
Problem 6.190TI: Simplify: (a) 11q1 (b) (11q)1 (c) (11q)1 (c) (11q)1 .
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Hello, I have been stuck on this question for a while now. I believe I did all the steps right thus far if I did not make a mistake somewhere down the line, I have not been able to find a way to know what A=? and what B=? could anyone spot a mistake that I could have made down the line or what might be my next step to finally finding what A and B are equal to? 

Thanks, you!

X-9 +² +3x-10 A x+s || + B X-2 x-9 (x+5)(x-2) X-9 = A (x-2) + B(x+5) AX-2A + B x + 5 B (A + B) x + (SB3 - 2 16) R = B =
Transcribed Image Text:X-9 +² +3x-10 A x+s || + B X-2 x-9 (x+5)(x-2) X-9 = A (x-2) + B(x+5) AX-2A + B x + 5 B (A + B) x + (SB3 - 2 16) R = B =
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