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What is the solution to these equations? (²)² = 2(x+12) [Select] (¹)² = 2(3-6) [Select] 525(x-3) [Select] [ Select] X = 3 x = -4 X = 6 X = 1 x = -3 x = 12 h

What is the solution to these equations? (²)² = 2(x+12) [Select] (¹)² = 2(3-6) [Select] 525(x-3) [Select] [ Select] X = 3 x = -4 X = 6 X = 1 x = -3 x = 12 h

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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**Title: Solving Exponential Equations** **Problem Statement:** What is the solution to these equations? 1. \(\left(\frac{1}{2}\right)^{2x} = 2^{(x+12)}\) - [Select] 2. \(\left(\frac{1}{8}\right)^x = 2^{(3x-6)}\) - [Select] 3. \(5^x = 25^{(x-3)}\) - [Select] **Answer Options (for each equation):** - \(x = -3\) - \(x = -4\) - \(x = 6\) - \(x = 1\) - \(x = 3\) - \(x = 12\)
Transcribed Image Text:**Title: Solving Exponential Equations** **Problem Statement:** What is the solution to these equations? 1. \(\left(\frac{1}{2}\right)^{2x} = 2^{(x+12)}\) - [Select] 2. \(\left(\frac{1}{8}\right)^x = 2^{(3x-6)}\) - [Select] 3. \(5^x = 25^{(x-3)}\) - [Select] **Answer Options (for each equation):** - \(x = -3\) - \(x = -4\) - \(x = 6\) - \(x = 1\) - \(x = 3\) - \(x = 12\)
Expert Solution
Step 1

1) (1/2)2x =2x+12

2) (1/8)x = 23x-6

3) 5x =25x-3.

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