What is the solution to these equations? (²)² = 2(x+12) [Select] (¹)² = 2(3-6) [Select] 525(x-3) [Select] [ Select] X = 3 x = -4 X = 6 X = 1 x = -3 x = 12 h
What is the solution to these equations? (²)² = 2(x+12) [Select] (¹)² = 2(3-6) [Select] 525(x-3) [Select] [ Select] X = 3 x = -4 X = 6 X = 1 x = -3 x = 12 h
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
Related questions
Question
![**Title: Solving Exponential Equations**
**Problem Statement:**
What is the solution to these equations?
1. \(\left(\frac{1}{2}\right)^{2x} = 2^{(x+12)}\)
- [Select]
2. \(\left(\frac{1}{8}\right)^x = 2^{(3x-6)}\)
- [Select]
3. \(5^x = 25^{(x-3)}\)
- [Select]
**Answer Options (for each equation):**
- \(x = -3\)
- \(x = -4\)
- \(x = 6\)
- \(x = 1\)
- \(x = 3\)
- \(x = 12\)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3400d2a4-5f5a-4a35-ac5a-1a41493ea47d%2F8fdfbd51-5adf-4beb-ad9f-745e7a3aab47%2Fona19ak_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Title: Solving Exponential Equations**
**Problem Statement:**
What is the solution to these equations?
1. \(\left(\frac{1}{2}\right)^{2x} = 2^{(x+12)}\)
- [Select]
2. \(\left(\frac{1}{8}\right)^x = 2^{(3x-6)}\)
- [Select]
3. \(5^x = 25^{(x-3)}\)
- [Select]
**Answer Options (for each equation):**
- \(x = -3\)
- \(x = -4\)
- \(x = 6\)
- \(x = 1\)
- \(x = 3\)
- \(x = 12\)
Expert Solution
Step 1
1) (1/2)2x =2x+12
2) (1/8)x = 23x-6
3) 5x =25x-3.
Step by step
Solved in 3 steps with 2 images
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