There are three random variables X, Y and Z,for which we know the following information E(X)= 6, V(X) = 18, E (Y) = 10, V(Y) = 22, E(Z) = 12, V (Z) = 4, cov(X, Y)= -12, cov(X, Z) = 5, cov(Y,Z) = 8. What is the V (3X-3Y-3Z)? O 666 O 267 O 333 O 531 O 414 O No answer

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