There are three random variables X, Y and Z, for which we know the following information E(X)= 6, V(X) = 18, E(Y) = 10, V(Y) = 22, E(Z) = 12, V(Z) = 4, cov(X,Y)=-12, cov(X, Z) = 5, cov(Y,Z) = B. What is the cov (3X,3X-3Y-3Z)? O 225 09 075 O 160 O 315 O No answer

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