Part II: Sections 2.1 - 2.7 7. Suppose that X is a discrete random variable with pmf f(x) c- |4 – r| - |2 – 2| for x = -3, 3, 6, where c is a constant. (a) Find e. -6X² +5 (b) Compute E 3

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A: Given : fx,yx,y = 6e-2x+3y   x≥0 , y≥00                    otherwise

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A: As asked by you, I have answered question (d). Please find the answer below. Thank you.

Q: tes, sno W inut E [XY] = E[X] E[Y] E [g1(X) g2(X)] = E [g1 (X)] E [g2 (X)1 and

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Q: What is the simple random walk on integers? Does it always return to the origin if p = ½ ? if p ≠ ½?

A: Lets consider the one step Simple random walk with zero as an Origin.

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Q: (ii) o Find

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A: Hello thankyou for the question As per the honor code, we are allowed to answer three parts at a…

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A: We have the sample space, S=x|x2-4x-5,x≤-1, x≥5

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A: It is highly useful in statistics . It is an application of discrete probability distribution .

Q: هدى الدالة 2x - = y هو. %3D

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Q: Example: (k (x+1) p(x) = P) is p.d.f. I x = 1,2,3,4 elsewhere Ep(x)=1 k(1+1)+ k(2+1)+k(3+1)+ k(4+1)…

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A: PGF of a Random Variable is given by, Gx(t) = Σ tx P(X=x)

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A: The correct option is option (e) None of these. The detailed solution is as follows below:

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