Suppose that X, Y, and Z are jointly distributed random variables, that is, they are defined on the same sample space. Suppose that we also have the following. E(X) = 4 E(Y) = -5 Var (X) = 26 Var (Y) = 19 Var (z) = 28 E(Z) = 8 Compute the values of the expressions below. E (5 + 32) - 0 () - 0 Var (2 - 4X) - 0 E(-31") - O
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Q: E(-27 + 3) = %3D -5z - x E %3D 4 Var (3x) + 3 = O %3D
A: According to the answering guidelines, we can answer only three subparts of a question and the rest…
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A: Given that, E(X) =-9 , E(Y) =-5, E(Z) =-1 Var(X) =3, Var(Y) =1, Var(Z) =34
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- Q2Suppose that X, Y, and Z are jointly distributed random variables, that is, they are defined on the same sample space. Suppose that we also have the following. Е (x) -0 Var(X) = E(Y)=-7 E (Z) = 4 = 42 Var(Y) = 39 var(Z)= Compute the values of the expressions below. E (4Y-1) = 0 믐 ? (2) - n E -1-Var(r) = 0 %3D E (2x*) = 0 oloCan help explain why the other options are correct and why this option is incorrect? Thank you!
- Q6. For two random variables X and Y, fxy(x, y) = 0.5 8(x+1) &(y)+0.1 8(x) 8{y) + 0.1 8(x) 8(y-2) + 0.4 &(x-1) S(y+2) + 0.2 &x– 1) d(y – 1) + 0.5 8(x – 1) 8(y – 3). Find, (a) The correlationAn ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of "heads" (h) and "tails" (t) which we write hth, ttt, etc. For each outcome, let N be the random variable counting the number of heads in each outcome. For example, if the outcome is ttt, then N (ttt) = 0. Suppose that the random variable X is defined in terms of N as follows: X = 2N−2N2 - 1. The values of X are given in the table below. Outcome ttt hht tth htt hhh tht hth thh Value of X −1 −5 −1 −1 −13 −1 −5 −5 Calculate the probabilities P (X = x) of the probability distribution of X. First, fill in the first row with the values of X. Then fill in the appropriate probabilities in the second row. Value x of X P (X = x)Suppose that X, Y, and Z are jointly distributed random variables, that is, they are defined on the same sample space. Suppose that we also have the following. E(X)=-9 E (Z) = 1 E (Y)=-6 Var(Y)=28 Var(Z) = 47 Var (X)=44 Compute the values of the expressions below. E (2-Z) = 0 E(X+32)=0 -5 -2-Var(4X) = 0 E(-x²) = 0 Continue □ X S M 31 Ⓒ2022 McGraw Hill LLC. All Rights Reserved
- 3. Let X₁, X2,..., Xn be iid random variables with mean and variance o2. Define the random variable X-L Z o/√√n where X = (X₁ + X2 + ... + Xn). Find the mean and variance of Z.If , and 02 be two unbiased estimators of 0 with variances of and o, respectively. What is the value of k so that the unbiased estimator Ô3 = 3kô, + (1- 3k)@, of 0 has a minimum variance. af (c) 3(a+of) (a) (b) af 3(0+o) (d) (e) NoneIf x, x2 ... Xn is a random sample from N (µ, o²) popula- tion, find súfficient estimator for µ and ơ.
- Let X be a random variable with probabilities as shown in Table 3.7. Table 3.7 Values of X and P(x) X(x;) -1 1 P(x,) 1 1 6. 3 2 Find (a) EĻX], (b) E[X²], (c) E[(2X+1)²] and (d) o,.An ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of "heads" (h) and "tails" (1) which we write hth, ttt, etc. For each outcome, let N be the random variable counting the number of heads in each outcome. For example, if the outcome is htt, then N (htt) = 1. Suppose that the random variable X is defined in terms of N as follows: X=2N-N2 -4, The values of X are given in the table below. Outcome hht tth hth thh tht ttt hhh htt Value of x -4 -3 -4 -4 -3 -4 -7 -3 Calculate the probabilities P(X=*) of the probability distribution of X. First, fill in the first row with the values of X. Then fill in the appropriate probabilities in the second row. Value of x _ _ _ p(X=x) _ _ _Suppose that X, Y, and Z are jointly distributed random variables, that is, they are defined on the same sample space. Suppose that we also have the following. E(X)=-6 E(Y)=-9 E(Z)=3 Var (X)=8 Var (Y)=14 Var (Z)=25 Compute the values of the expressions below. E (-1- 37) - I -2x - 5z 4 Var (47) - 2 - I e(32°) - [I Dlo